长/内分裂意外的结果

本文介绍了长/内分裂意外的结果的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有这样的价值：

long millis = 11400000; int consta = 86400000; double res = millis/consta;

问题是：为什么 res code> 0.0 （而不是ca. 0.131944 ）？它存储在 double 中，所以应该没有四舍五入？

The question is: why res equals 0.0 (instead of ca. 0.131944)? It's stored in double so there should be no rounding right?

推荐答案

当您使用二进制运算符时，两个参数应该是相同的类型，结果也将在它们的类型中。当你想划分（int）/（long），它变成（long）/（long）结果是（long）。你应该使用（double）/（long）或（int）/（double）获得双重结果。由于double大于int和long，int和long将在（double）/（long）和（int）/（双）

When you are using a binary operator, both arguments should be of a same type and the result will be in their type too. When you want to divide (int)/(long) it turns into (long)/(long) and the result is (long). you shouldmake it (double)/(long) or (int)/(double) to get a double result. Since double is greater that int and long, int and long will be turned into double in (double)/(long) and (int)/(double)