我有这样的价值:
long millis = 11400000; int consta = 86400000; double res = millis/consta;问题是:为什么 res code> 0.0 (而不是ca. 0.131944 )?它存储在 double 中,所以应该没有四舍五入?
The question is: why res equals 0.0 (instead of ca. 0.131944)? It's stored in double so there should be no rounding right?
推荐答案当您使用二进制运算符时,两个参数应该是相同的类型,结果也将在它们的类型中。当你想划分(int)/(long),它变成(long)/(long)结果是(long)。你应该使用(double)/(long)或(int)/(double)获得双重结果。由于double大于int和long,int和long将在(double)/(long)和(int)/(双)
When you are using a binary operator, both arguments should be of a same type and the result will be in their type too. When you want to divide (int)/(long) it turns into (long)/(long) and the result is (long). you shouldmake it (double)/(long) or (int)/(double) to get a double result. Since double is greater that int and long, int and long will be turned into double in (double)/(long) and (int)/(double)
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