Libgdx阵列如何获得最后一个项目?

编程入门行业动态更新时间:2024-10-08 12:43:12

本文介绍了Libgdx阵列如何获得最后一个项目?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

当相机的Y位置高于上次创建的存储桶"时，我想更改存储桶"的Y位置Y位置:"create()"方法中有我的代码

I want to change Y position of "bucket", when camera Y position is higher than "last created bucket" Y position: There is my code in "create()" method

buckets = new Array<Bucket>(); for(int i=1;i<BUCKET_COUNT;i++){ buckets.add(new Bucket(world,(rand.nextInt((int)W)-45)/PPM,BUCKET_MARGIN*i/PPM)); }

我正在"render()"方法中这样做:

And I am doing like this in "render()" method:

for(Bucket bucket : buckets){ if(cam.position.y > buckets.peek().getBody().getPosition().y){ bucket.repos(rand.nextInt((int)W)/PPM,buckets.size+BUCKET_MARGIN/PPM); } }

repos():

public void repos(float x, float y){ setPosition(x, y);//Bucket class is extends Sprite }

但是它不起作用，我也不知道如何解决这个问题

But it doesn't work and I don't know how to solve this problem

我想知道如何从那些数组中获得 last 个项目?

I want to know how to get last item from those array?

推荐答案

您应该尝试一下

if(cam.position.y > buckets.peek().getPosition().y){ for(Bucket bucket : buckets){ bucket.repos(rand.nextInt((int)W)/PPM,buckets.size+BUCKET_MARGIN/PPM); } }

在此y位置中，未正确指定存储桶，因为根据您的代码，所有存储桶都设置为特定的y位置.

In this y position of buckets are not properly specified because according to your code all bucket set to particular y position.

编辑

if(cam.position.y > buckets.peek().getPosition().y){ for(Bucket bucket : buckets){ bucket.repos(rand.nextInt((int)W)/PPM,cam.position.y+bucket.getPositon().y); } }