我有一个Thing对象的数组,我想使用返回Observable<ConvertedThing>的异步函数将其转换为ConvertedThing对象.
I have an array of Thing objects that I want to convert to ConvertedThing objects, using an asynchronous function that returns Observable<ConvertedThing>.
我想创建一个Observable<[ConvertedThing]>,当所有转换完成后,该Observable<[ConvertedThing]>会发出一个值.
I'd like to create an Observable<[ConvertedThing]> that emits one value when all the conversions have completed.
如何实现?任何帮助,不胜感激!
How can this be accomplished? Any help much appreciated!
推荐答案您可以使用 .merge() 将可观察变量数组组合成单个可观察变量,然后使用 .toArray() 在单个事件中将它们作为列表获取.
You can use .merge() to combine the array of observables into a single observable, and then use .toArray() to get them as a list in a single event.
对于RxSwift 3+,请使用:
For RxSwift 3+ use:
let arrayOfObservables: [Observable<E>] = ... let singleObservable: Observable<E> = Observable.from(arrayOfObservables).merge() let wholeSequence: Observable<[E]> = singleObservable.toArray()对于以前的版本:
let arrayOfObservables: [Observable<E>] = ... let singleObservable: Observable<E> = arrayOfObservables.toObservable().merge() let wholeSequence: Observable<[E]> = singleObservable.toArray()更多推荐
如何从可观察对象数组创建可观察对象数组?
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