假设我有以下内容:
IEnumerable<Task<TimeSpan>> tasks = //... TimeSpan[] results = await Task.WhenAll(tasks); // Handle results等到我可以处理所有任务必须完成的结果时.
By the time I can handle the results all the task must have finished.
是否有一种方法可以按需处理每个结果??
Is there a way to handle each result on demand?
就像注册一个将在任务完成时执行的委托/回调一样:
Like registering a delegate / callback that will get executed when a task is completed:
IEnumerable<Task<TimeSpan>> tasks = //... await Task.WhenAll(tasks, result => { // A task has finished. This will get executed. // result is of type TimeSpan });推荐答案
有没有一种方法可以按需处理每个结果?
Is there a way to handle each result on demand?
是的,您使用WhenAny而不是WhenAll ...或在每个任务上调用ContinueWith.
Yes, you use WhenAny instead of WhenAll... or call ContinueWith on each task.
例如,对于WhenAny方法:
ISet<Task<TimeSpan>> tasks = new HashSet<Task<TimeSpan>>(...); while (tasks.Count != 0) { var task = await Task.WhenAny(tasks); // Use task here tasks.Remove(task); }您可以使用另一个选项,将原始任务序列转换为按顺序完成但给出相同结果的任务序列.详细信息在此博客帖子,但结果是您可以使用:
There's another option you could use, where you transform the original sequence of tasks into a sequence of tasks which completes in order, but giving the same results. Details are in this blog post, but the result is that you can use:
foreach (var task in tasks.InCompletionOrder()) { var result = await task; // Use the result }更多推荐
Task.WhenAll中是否有任务完成时的回调
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