通过MemberExpression获取属性类型

本文介绍了通过MemberExpression获取属性类型的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

请问类似的问题 here ，假设这个类型：

I ask similar question here , assume this type:

public class Product { public string Name { get; set; } public string Title { get; set; } public string Category { get; set; } public bool IsAllowed { get; set; } }

而这个使用 MemberExpression ：

public class HelperClass<T> { public static void Property<TProp>(Expression<Func<T, TProp>> expression) { var body = expression.Body as MemberExpression; if(body == null) throw new ArgumentException("'expression' should be a member expression"); string propName = body.Member.Name; Type proptype = null; } }

我用它像这样：

HelperClass<Product>.Property(p => p.IsAllowed);

在 HelperClass 我只需要属性名称在这个例子中， IsAllowed ）和属性类型（在这个例子中 Boolean ）所以我可以获取属性名称，获取属性类型。我在调试中看到属性类型如下图所示：

in HelperClass I just need property name(in this example IsAllowed) and property type (in this example Boolean) So I can get property name but I can't get property type. I see the property type in debugging as following picture shown:

那么你建议如何获取属性类型？

So what is your suggestion to get property type?

推荐答案

尝试将 body.Member 转换为 PropertyInfo

public class HelperClass<T> { public static void Property<TProp>(Expression<Func<T, TProp>> expression) { var body = expression.Body as MemberExpression; if (body == null) { throw new ArgumentException("'expression' should be a member expression"); } var propertyInfo = (PropertyInfo)body.Member; var propertyType = propertyInfo.PropertyType; var propertyName = propertyInfo.Name; } }