将JAXB生成的类用于需要带有模式的整数的元素

本文介绍了将JAXB生成的类用于需要带有模式的整数的元素的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我的XML Schema中有一个元素定义如下：

I have an element in my XML Schema that is defined as follows:

<xs:complexType name="MyNumberCodeType"> <xs:sequence> <xs:element name="Code" type="NumberCodeValueType" maxOccurs="unbounded" /> </xs:sequence> </xs:complexType>

其中NumberCodeValueType为：

Where NumberCodeValueType is:

<xs:simpleType name="NumberCodeValueType"> <xs:restriction base="xs:int"> <xs:pattern value="[0-7]{7}"/> </xs:restriction> </xs:simpleType>

也就是说，我的号码可以从前导0开始。我无法修改此架构。我正在使用JAXB来生成我的Java类。不幸的是， Code 元素的访问器采用整数列表作为参数，这意味着所有前导0被剥离（因为，据我所知，没有办法使用整数类型时，在Java中保持领先0）！

That is, my number can start with leading 0s. I can NOT modify this schema. I am using JAXB to generate my Java classes. Unfortunately, the accessor for the Code element takes a list of integers as the argument which means all leading 0s are stripped off (because, from what I can tell, there's no way to keep leading 0s in Java when using an integer type)!

有什么方法可以解决这个问题吗？

Is there any way I can fix this?

感谢您的帮助！

推荐答案

您可以执行以下操作：

NumberFormatter

您可以通过编写自己的格式化程序来完成此操作：

You can do this by writing your own formatter:

package forum7182533; public class NumberFormatter { public static String printInt(Integer value) { String result = String.valueOf(value); for(int x=0, length = 7 - result.length(); x<length; x++) { result = "0" + result; } return result; } public static Integer parseInt(String value) { return Integer.valueOf(value); } }

XMLSchema（格式。 xsd）

然后当您要从XML Schema生成类时：

Then when you are going to generate your classes from your XML Schema:

<?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="www.w3/2001/XMLSchema"> <xs:element name="root"> <xs:complexType> <xs:sequence> <xs:element name="number" type="NumberCodeValueType" /> </xs:sequence> </xs:complexType> </xs:element> <xs:simpleType name="NumberCodeValueType"> <xs:restriction base="xs:int"> <xs:pattern value="[0-7]{7}" /> </xs:restriction> </xs:simpleType> </xs:schema>

bindings.xml

您将利用JAXB绑定文件来引用您的格式化程序：

You will leverage a JAXB bindings file to reference your formatter:

<jxb:bindings xmlns:xs="www.w3/2001/XMLSchema" xmlns:jxb="java.sun/xml/ns/jaxb" version="2.1"> <jxb:bindings schemaLocation="format.xsd"> <!--jxb:bindings node="//xs:simpleType[@name='NumberCodeValueType']" --> <jxb:bindings node="//xs:element[@name='number']"> <jxb:property> <jxb:baseType> <jxb:javaType name="java.lang.Integer" parseMethod="forum7182533.NumberFormatter.parseInt" printMethod="forum7182533.NumberFormatter.printInt" /> </jxb:baseType> </jxb:property> </jxb:bindings> </jxb:bindings> </jxb:bindings>

XJC致电

绑定文件在XJC调用中被引用为：

The bindings file is referenced in the XJC call as:

xjc -d out -p forum7182533 -b bindings.xml format.xsd

Adapter1

这将导致创建一个利用格式化程序的 XmlAdapter ：

This will cause an XmlAdapter to be created that leverages your formatter:

package forum7182533; import javax.xml.bind.annotation.adapters.XmlAdapter; public class Adapter1 extends XmlAdapter<String, Integer> { public Integer unmarshal(String value) { return (forum7182533.NumberFormatter.parseInt(value)); } public String marshal(Integer value) { return (forum7182533.NumberFormatter.printInt(value)); } }

Root

将使用 @XmlJavaTypeAdapter从您的域对象引用 XmlAdapter 注释：

The XmlAdapter will be referenced from your domain object using the @XmlJavaTypeAdapter annotation:

package forum7182533; import javax.xml.bind.annotation.XmlAccessType; import javax.xml.bind.annotation.XmlAccessorType; import javax.xml.bind.annotation.XmlElement; import javax.xml.bind.annotation.XmlRootElement; import javax.xml.bind.annotation.XmlType; import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter; @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "", propOrder = { "number" }) @XmlRootElement(name = "root") public class Root { @XmlElement(required = true, type = String.class) @XmlJavaTypeAdapter(Adapter1 .class) protected Integer number; public Integer getNumber() { return number; } public void setNumber(Integer value) { this.number = value; } }

演示

现在，如果您运行以下演示代码：

Now if you run the following demo code:

package forum7182533; import javax.xml.bind.JAXBContext; import javax.xml.bind.Marshaller; public class Demo { public static void main(String[] args) throws Exception { JAXBContext jc = JAXBContext.newInstance(Root.class); Root root = new Root(); root.setNumber(4); Marshaller marshaller = jc.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); marshaller.marshal(root, System.out); } }

输出

您将获得所需的输出：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <root> <number>0000004</number> </root>