在python中列出嵌套字典

本文介绍了在python中列出嵌套字典的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个列表如下

['item1', 'item2', 'item3', 'item4']

我想从上面的列表中构建一个字典如下

I want to construct a dictionary from the above list as follows

{ "item1": { "item2": { "item3": "item4" } } }

列表中的项目数量是动态的。字典将是一个嵌套字典，直到它到达列表的最后一个元素。 python有没有办法这样做？

The number of items in the list is dynamic. The dictionary will be a nested dictionary till it reaches the last element of the list. Is there any way in python to do this?

推荐答案

简单单行：

a = ['item1', 'item2', 'item3','item4'] print reduce(lambda x, y: {y: x}, reversed(a))

为了更好地理解上述代码可以扩展为：

For better understanding the above code can be expanded to:

def nest_me(x, y): """ Take two arguments and return a one element dict with first argument as a value and second as a key """ return {y: x} a = ['item1', 'item2', 'item3','item4'] rev_a = reversed(a) # ['item4', 'item3', 'item2','item1'] print reduce( nest_me, # Function applied until the list is reduced to one element list rev_a # Iterable to be reduced ) # {'item1': {'item2': {'item3': 'item4'}}}