在嵌套字典中查找键

本文介绍了在嵌套字典中查找键的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如何在不使用for循环和直接访问该变量的情况下，在python的嵌套字典中查找特定键.

How to find a specific key in a nested dictionary in python without using a for loop and directly accessing that variable.

我有一个看起来类似于嵌套字典的json文件.如何在其中找到特定的关键字?

I have a json file which looks similar to a nested dictionary. How could i find a specific keyword in it?

data={ u'session': { u'new': True, u'sessionId': u'amzn1.echo-api.session.fae41185-1c00-4463-b890-0833c32a2b43', u'user': { u'userId': u'amzn1.ask.account.AHEEJXVACGJ2XZV4QRNFSIW7LDHAXEUB7WTZXC6777CLHLS4ITEWD6RMQLNXG5ECXFP3WRAQDH53EZUZ2GOFC52SNZ5NI5L7LXG3HMS6ORA2DNVT3TFYL5N5WE4GTSFM4PS7TGYXXQYCMOCRVBEPXBNHV2G6DPIUP3XPHCSIKJF26SOSZZAD4TRLHJA66JPEVDWJMRBH7AL2WUA' }, u'application': { u'applicationId': u'amzn1.ask.skill.ec977129-bcaf-462c-85ce-03c1f7a2b1f8' } }, u'version': u'1.0', u'request': { u'locale': u'en-IN', u'timestamp': u'2018-01-12T10:11:46Z', u'dialogState': u'STARTED', u'intent': { u'slots': { u'product': { u'name': u'product', u'confirmationStatus': u'NONE' }, u'subcategories': { u'resolutions': { u'resolutionsPerAuthority': [ { u'status': { u'code': u'ER_SUCCESS_MATCH' }, u'values': [ { u'value': { u'name': u'milk', u'id': u'ecbdb882ae865a07d87611437fda0772' } } ], u'authority': u'amzn1.er-authority.echo-sdk.amzn1.ask.skill.ec977129-bcaf-462c-85ce-03c1f7a2b1f8_Certification.subcategories' } ] }, u'name': u'subcategories', u'value': u'milk', u'confirmationStatus': u'NONE' }, u'brand': { u'resolutions': { u'resolutionsPerAuthority': [ { u'status': { u'code': u'ER_SUCCESS_MATCH' }, u'values': [ { u'value': { u'name': u'nestle', u'id': u'099e3726deeeb0f04f86d49093eebbb2' } } ], u'authority': u'amzn1.er-authority.echo-sdk.amzn1.ask.skill.ec977129-bcaf-462c-85ce-03c1f7a2b1f8_Certification.brand' } ] }, u'name': u'brand', u'value': u'nestle', u'confirmationStatus': u'NONE' }, u'categories': { u'name': u'categories', u'confirmationStatus': u'NONE' }, u'more_n_repeat': { u'name': u'more_n_repeat', u'confirmationStatus': u'NONE' } }, u'name': u'user_says', u'confirmationStatus': u'NONE' }, u'requestId': u'amzn1.echo-api.request.432d4866-f781-418a-88a8-5d2b8d341409', u'type': u'IntentRequest' }, u'context': { u'AudioPlayer': { u'playerActivity': u'IDLE' }, u'System': { u'device': { u'deviceId': u'amzn1.ask.device.AHJQTUWHP2J7MS7WFE45RNWOO32KO4DPTY4HKNU66YPLG3BOFXRFVA32JEILOKUADFOGC4JCTM4CFOPN6MJP2BEQNF3TPOKCPGLHYEDJBLYS5QOIBPKD7SZALTCVKK2YUP7WWUA5XHC2ATFS4MYLXA7I4UVQ', u'supportedInterfaces': { u'AudioPlayer': { } } }, u'application': { u'applicationId': u'amzn1.ask.skill.ec977129-bcaf-462c-85ce-03c1f7a2b1f8' }, u'apiAccessToken': u'eyJ0eXAiOiJKV1QiLCJhbGciOiJSUzI1NiIsImtpZCI6IjEifQ.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.DsQSWRNaAlNyzdOyCxaYa3n193RxYJCul0RFc-prCDXxpzIYRxJ6wrZkAS7BCSezK-6hcL8wuiFGdVtQPQk57mL8TBjxwczyc_6vHMjeQEzbcIXGE-xLx-lifNxIpH6w9YQNLavMsLIEEsMP0X1dMXDiBXBAe9A6neb0EdTRi6mdJaUC6Lvx6YnZrY1Xu8scm3vqi47BHKYsGaO508m9vZgVIjmz3st5LHW3Uc5svsK0T3P3aew0iH7K9pzpfm1mRF6POd4jLpyoikdLY4HEDQOC9RSLN4W0SvTw1-y8UEerkQolHaJWQdv86F1dqKjlbaF1zRAmWRVYPPVp7gqFag', u'user': { u'userId': u'amzn1.ask.account.AHEEJXVACGJ2XZV4QRNFSIW7LDHAXEUB7WTZXC6777CLHLS4ITEWD6RMQLNXG5ECXFP3WRAQDH53EZUZ2GOFC52SNZ5NI5L7LXG3HMS6ORA2DNVT3TFYL5N5WE4GTSFM4PS7TGYXXQYCMOCRVBEPXBNHV2G6DPIUP3XPHCSIKJF26SOSZZAD4TRLHJA66JPEVDWJMRBH7AL2WUA' }, u'apiEndpoint': u'api.eu.amazonalexa' } } }

现在我需要从这本词典中找到品牌价值. 有没有办法在单行代码中检索它.

Now i need to find brand value from this dictionary. Is there any way of retrieving it in single line of code.

推荐答案

outer_keys = filter(lambda x: my_key in x, my_dict.keys()) result = my_dict[next(outer_keys)][my_key]