如何仅为iPhone 6和6 Plus限制我的应用程序？

本文介绍了如何仅为iPhone 6和6 Plus限制我的应用程序？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

背景

我正在开发目前在iPad设备上运行的填字游戏应用。 Apple最近发布了iPhone 6和iPhone 6+设备，幸运的是它拥有更大的屏幕，因此可以合法地运行我的游戏（我已经在iPhone 5S设备上测试了我的游戏，如果发现它不舒服用户以这样的屏幕尺寸运行。）

I'm developing a Crossword game app that currently runs on iPad devices. Apple has recently released iPhone 6 and iPhone 6+ devices, which fortunately have a bigger screen and thus become eligibly to run my game (I have tested my game on a iPhone 5S device and if found that it was not pleasant to the user to run in such screen size).

通过这种方式，我决定将我的应用程序迁移到Universal二进制文件，其中包括对iPhone 6，iPhone 6 Plus的支持和iPad设备。

In this way, I decided to migrate my app to an Universal binary that would include support for iPhone 6, iPhone 6 Plus and iPad devices.

问题

是有没有办法限制我的iOS应用程序仅在iPhone 6和iPhone 6+设备上运行？

或者，至少：

有没有办法限制我的iOS应用仅在iPhone 6+设备上运行？

推荐答案

我知道这可能太晚了，无论如何可能都不回答这个问题，但我想'是什么heck' - 确定设备范围是一个很好的代码，在cas中您可能需要不同的功能。

I know it's probably way too late, and probably doesn't answer the question anyway, but I figured 'what the heck' – it's a nice bit of code to determine ranges of devices, where in cases you may want different functionality.

#import <sys/sysctl.h> -(BOOL)isANewerDevice{ size_t size; sysctlbyname("hw.machine", NULL, &size, NULL, 0); char *machine = malloc(size); sysctlbyname("hw.machine", machine, &size, NULL, 0); NSString *platform = [NSString stringWithCString:machine encoding:NSUTF8StringEncoding]; free(machine); NSString * ending = [platform substringFromIndex:[platform length]-3]; double convertedNumber = [[ending stringByReplacingOccurrencesOfString:@"," withString:@"."] doubleValue]; //Devices listed here: stackoverflow/questions/19584208/identify-new-iphone-model-on-xcode-5-5c-5s if ([platform containsString:@"iPhone"]) { if (convertedNumber >= 7.1) { // 6 and above return YES; }else{ return NO; //less than a 6 (ie 5S and below) } }else if ([platform containsString:@"iPad"]){ if (convertedNumber >= 5.3) { //iPad Air 2 and above return YES; }else{ return NO; //iPad Mini 3 and below } } //Failsafe return NO; }

代码中注释的链接：在xcode（5,5c，5s）上识别新的iPhone型号

注意。由于 containsString ，这将在小于8的iOS版本上崩溃。要支持< 8.0，请尝试使用以下代码重新拟合此函数stackoverflow/a/26416172/1197723

Note. Due to having containsString, this will crash on iOS versions less than 8. To support <8.0, try using the following code to retro-fit this function stackoverflow/a/26416172/1197723

玩得开心！