我创建了一个在任务栏中运行的应用程序。当用户单击该应用程序时,它将弹出等。当我的一个朋友登录时,我想要的功能与MSN中的功能类似。显然,这是一个吐司弹出窗口吗? 我基本上希望每20分钟从任务栏上的应用程序中弹出吐司样式弹出的东西。
I have created an application that runs in the taskbar. When a user clicks the application it pops up etc. What I would like is similar functionality to that in MSN when one of my friends logs in. Apparently this is know as a toast popup? I basically want something to popup from every 20 minutes toast style fom the application in the taskbar.
我现有的应用程序是使用用C#编写的winforms。 3.5
My existing application is winforms based written in C# with 3.5
推荐答案这很简单。您只需要在窗口外的区域中设置窗口并设置其位置的动画效果,直到完全可见即可。下面是示例代码:
This is pretty simple. You just need to set window in off-screen area and animate it's position until it is fully visible. Here is a sample code:
public partial class Form1 : Form { private Timer timer; private int startPosX; private int startPosY; public Form1() { InitializeComponent(); // We want our window to be the top most TopMost = true; // Pop doesn't need to be shown in task bar ShowInTaskbar = false; // Create and run timer for animation timer = new Timer(); timer.Interval = 50; timer.Tick += timer_Tick; } protected override void OnLoad(EventArgs e) { // Move window out of screen startPosX = Screen.PrimaryScreen.WorkingArea.Width - Width; startPosY = Screen.PrimaryScreen.WorkingArea.Height; SetDesktopLocation(startPosX, startPosY); base.OnLoad(e); // Begin animation timer.Start(); } void timer_Tick(object sender, EventArgs e) { //Lift window by 5 pixels startPosY -= 5; //If window is fully visible stop the timer if (startPosY < Screen.PrimaryScreen.WorkingArea.Height - Height) timer.Stop(); else SetDesktopLocation(startPosX, startPosY); } }更多推荐
如何在我的应用程序中添加吐司样式弹出窗口?
发布评论