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问题描述
当我按Enter键时,登录页面的C#代码是什么.
what is the c# code for login page when i press enter key.
推荐答案分三个步骤: -登录表单应为模式表单(即与ShowDialog一起显示) -它应该有一个OK/Login/etc按钮,其DialogResult设置为OK(导致窗体被关闭,并且控件在按下按钮时返回到导致ShowDialog的代码) -表单应将其AcceptButton属性设置为该按钮(导致在按下Enter键时按下"按钮) There are three steps: - the login form should be modal (i.e. shown with ShowDialog) - it should have an OK/Login/etc button with its DialogResult set to OK (causes the form to be closed and control to return to the code that caused ShowDialog when the button is pressed) - the form should have its AcceptButton property set to that button (causes the button to be ''pressed'' when Enter is pressed)
您需要为其设置一个表单属性. Hi, You need to set a Form Property for it. Form1.AcceptButton=btnLogin;
希望它对您有用. 问候 AR
Hope it will work for you. Regards AR
您必须将以下代码设置为txtname.KeyUp和txtPassword.KeyUp 命令 You have to set the below code to txtname.KeyUp And to txtPassword.KeyUp command if (e.KeyCode=13) { Call LoginEvent(); }
您可以将登录代码设置为LoginEvent() 谢谢.
You can set your Login code to LoginEvent() Thanks.
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基于C#代码窗口的应用程序
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