如何在C#中解析数学表达式?

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本文介绍了如何在C#中解析数学表达式?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述

可能重复: 在.NET中有字符串数学评估器吗?

C#可以将数学表达式如y = 3 * x + 3解析成字符串吗?如果是这样的话? 感谢您的帮助。

Can C# parse mathematical expressions such as y=3*x + 3 into string? If so, ho? I appreciate your help.

推荐答案

这里有一些我之前写过的代码解析中缀(操作符操作数运算符)方程式的代码。 有一些小的类和帮助函数缺少,但它应该是相当容易实现它们。如果你需要他们或任何帮助,让我知道,我可以上传他们在某个地方。

Here's a bit of code I wrote a while ago to parse infix (operator operand operator) equations. There are some small classes and helper functions missing, but it should be fairly easy to implement them. If you need them or any help with it, let me know and I can upload them somewhere.

这是Dijkstra的分流算法

It's a basic implementation of Dijkstra's Shunting-yard algorithm

public Operand ExpressionTree { get; private set; } private Stack<Operands.Operand> stack = new Stack<InfixParser.Operands.Operand>(); private Queue<Operands.Operand> outputQueue = new Queue<InfixParser.Operands.Operand>(); private void ParseFormulaString() { //Dijkstra's Shunting Yard Algorithm Regex re = new Regex(@"([\+\-\*\(\)\^\/\ ])"); List<String> tokenList = re.Split(formulaString).Select(t => t.Trim()).Where(t => t != "").ToList(); for (int tokenNumber = 0; tokenNumber < tokenList.Count(); ++tokenNumber) { String token = tokenList[tokenNumber]; TokenClass tokenClass = GetTokenClass(token); switch (tokenClass) { case TokenClass.Value: outputQueue.Enqueue(new Value(token)); break; case TokenClass.Function: stack.Push(new Function(token, 1)); break; case TokenClass.Operator: if (token == "-" && (stack.Count == 0 || tokenList[tokenNumber - 1] == "(")) { //Push unary operator 'Negative' to stack stack.Push(new Negative()); break; } if (stack.Count > 0) { String stackTopToken = stack.Peek().Token; if (GetTokenClass(stackTopToken) == TokenClass.Operator) { Associativity tokenAssociativity = GetOperatorAssociativity(token); int tokenPrecedence = GetOperatorPrecedence(token); int stackTopPrecedence = GetOperatorPrecedence(stackTopToken); if (tokenAssociativity == Associativity.Left && tokenPrecedence <= stackTopPrecedence || tokenAssociativity == Associativity.Right && tokenPrecedence < stackTopPrecedence) { outputQueue.Enqueue(stack.Pop()); } } } stack.Push(new BinaryOperator(token, Operator.OperatorNotation.Infix)); break; case TokenClass.LeftParen: stack.Push(new LeftParenthesis()); break; case TokenClass.RightParen: while (!(stack.Peek() is LeftParenthesis)) { outputQueue.Enqueue(stack.Pop()); } stack.Pop(); if (stack.Count > 0 && stack.Peek() is Function) { outputQueue.Enqueue(stack.Pop()); } break; } if (tokenClass == TokenClass.Value || tokenClass == TokenClass.RightParen) { if (tokenNumber < tokenList.Count() - 1) { String nextToken = tokenList[tokenNumber + 1]; TokenClass nextTokenClass = GetTokenClass(nextToken); if (nextTokenClass != TokenClass.Operator && nextTokenClass != TokenClass.RightParen) { tokenList.Insert(tokenNumber + 1, "*"); } } } } while (stack.Count > 0) { Operand operand = stack.Pop(); if (operand is LeftParenthesis || operand is RightParenthesis) { throw new ArgumentException("Mismatched parentheses"); } outputQueue.Enqueue(operand); } String foo = String.Join(",", outputQueue.Select(t => t.Token).ToArray()); String bar = String.Join("", tokenList.ToArray()); Stack<Operand> expressionStack = new Stack<Operand>(); while (outputQueue.Count > 0) { Operand operand = outputQueue.Dequeue(); if (operand is Value) { expressionStack.Push(operand); } else { if (operand is BinaryOperator) { BinaryOperator op = (BinaryOperator)operand; Operand rightOperand = expressionStack.Pop(); Operand leftOperand = expressionStack.Pop(); op.LeftOperand = leftOperand; op.RightOperand = rightOperand; } else if (operand is UnaryOperator) { ((UnaryOperator)operand).Operand = expressionStack.Pop(); } else if (operand is Function) { Function function = (Function)operand; for (int argNum = 0; argNum < function.NumArguments; ++argNum) { function.Arguments.Add(expressionStack.Pop()); } } expressionStack.Push(operand); } } if (expressionStack.Count != 1) { throw new ArgumentException("Invalid formula"); } ExpressionTree = expressionStack.Pop(); } private TokenClass GetTokenClass(String token) { double tempValue; if (double.TryParse(token, out tempValue) || token.Equals("R", StringComparison.CurrentCultureIgnoreCase) || token.Equals("S", StringComparison.CurrentCultureIgnoreCase)) { return TokenClass.Value; } else if (token.Equals("sqrt", StringComparison.CurrentCultureIgnoreCase)) { return TokenClass.Function; } else if (token == "(") { return TokenClass.LeftParen; } else if (token == ")") { return TokenClass.RightParen; } else if (binaryInfixOperators.Contains(token)) { return TokenClass.Operator; } else { throw new ArgumentException("Invalid token"); } } private Associativity GetOperatorAssociativity(String token) { if (token == "^") return Associativity.Right; else return Associativity.Left; } private int GetOperatorPrecedence(String token) { if (token == "+" || token == "-") { return 1; } else if (token == "*" || token == "/") { return 2; } else if (token == "^") { return 3; } else { throw new ArgumentException("Invalid token"); } }

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如何在C#中解析数学表达式?

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