检查Excel文件是否受密码保护

本文介绍了检查Excel文件是否受密码保护的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试通过VBA打开一个Excel（xlsm）文件。它可能使用（或已知的）密码来保护也可能不受保护。我正在使用以下代码：

On Error Resume Next Workbooks.Open filename，Password：= user_entered_pw 打开=（Err.Number = 0）错误转到0

现在，这个如果工作簿有密码，工作正常。但如果没有保护，则无法打开。显然这是XL2007中的一个错误，如果还有工作簿结构保护激活。 （ vbaadventures.blogspot/2009 /01/possible-error-in-excel-2007.html ）。在旧的XL2003上，提供密码将打开无保护和密码保护的文件。

我试过：

Workbooks.Open filename，Password：= user_entered_pw If（Err.Number<> 0）Then workbooks.open filename pre>

这适用于未受保护和受保护的文件。但是，如果用户输入错误的密码，它将进入第二行，弹出输入密码提示，这不是我想要的。

如何解决这个问题？

解决方案

为了纪录 - 原因确实是我正在开放的工作簿的结构保护。 我可以通过禁用结构保护来规避问题，并在Workbook_Open（）（在受保护的工作簿中）重新保护。

结构保护无效，即使没有密码， Workbooks.Open 与密码也不会失败。 p>

由于我通过VBA方法打开，VBA代码已经被信任，意味着一定会调用Workbook_Open方法。

I am trying to open an Excel (xlsm) file via VBA. It may or may not be protected with a (known) password. I am using this code:

On Error Resume Next Workbooks.Open filename, Password:=user_entered_pw opened = (Err.Number=0) On Error Goto 0

Now, this works fine if the workbook has a password. But if it is unprotected, it can NOT be opened. Apparently this is a bug in XL2007 if there is also workbook structure protection active. (vbaadventures.blogspot/2009/01/possible-error-in-excel-2007.html). On old XL2003, supplying a password would open both unprotected and password protected file.

I tried:

Workbooks.Open filename, Password:=user_entered_pw If (Err.Number <> 0) Then workbooks.open filename

This works for unprotected and protected file. However if the user enters a wrong password it runs into the second line and pops up the "enter password" prompt, which I do not want.

How to get around this?

解决方案

For the record - the reason was indeed the structure protection of the workbook I was opening. I could circumvent the problem by disabling structure protection, and re-protecting in Workbook_Open() (in the protected workbook).

With structure protection inactive, Workbooks.Open with password does not fail even when there is no password.

Since I am opening via a VBA method, the VBA code is already trusted, meaning the Workbook_Open method will surely be called.