替换字符串中的元素

编程入门 行业动态 更新时间:2024-10-25 10:20:51
本文介绍了替换字符串中的元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述

假设我的str持有: str =helloHowAreYou; 现在我想将字符串的索引从特定位置向后移动并且 我的新字符串将包含。 str =heoHowAreYou。 我的代码输出是str =heoHowAreYou Y, 任何帮助将不胜感激 我尝试过:

#include< iostream> #include< cstring> using namespace std; void shift(string arr,int be) { int j = be; while(arr [j]!='\ 0') { j ++; } int k = j-2; while(be< = k) { arr [be] = arr [be + 2]; 是++; } cout<< arr; } int main(int argc,char const * argv []) { string str; str =helloHowAreyou; shift(str,2); 返回0; }

解决方案

据我了解你的代码,它无法产生规定的输出。 问题的一部分,你没有减少字符串的长度。 有一个工具可以让你看到你的代码是什么正在做,它的名字是调试器。它也是一个很好的学习工具,因为它向你展示了现实,你可以看到哪种期望与现实相符。 当你不明白你的代码在做什么或为什么它做它做的时候,答案就是答案是调试器。 使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况,调试器允许您逐行执行第1行并在执行时检查变量,这是一个令人难以置信的学习工具。 调试器 - 维基百科,免费的百科全书 [ ^ ] 掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ] 使用Visual Studio 2010进行基本调试 - YouTube [ ^ ] 调试器在这里显示你的代码在做什么你的任务是与它应该做的事情进行比较。 调试器中没有魔法,它没有发现错误,它只是帮助你。当代码没有达到预期的效果时,你就接近了一个错误。

你的例子在位置2删除了2个字符。 有一个 std :: string 方法可以做到这一点: std :: basic_string :: erase - cppreference [ ^ ]:

string str =helloHowAreyou; str.erase(2,2); cout<< STR;

suppose my str holds: str="helloHowAreYou"; Now i want to shift the indexes of the string to backward from a particular position and my new string will contain. str="heoHowAreYou". My code output is str="heoHowAreYou Y", Any help will be appreciated What I have tried:

#include <iostream> #include<cstring> using namespace std; void shift(string arr,int be) { int j=be; while(arr[j]!='\0') { j++; } int k=j-2; while(be<=k) { arr[be]=arr[be+2]; be++; } cout<<arr; } int main(int argc, char const *argv[]) { string str; str="helloHowAreyou"; shift(str,2); return 0; }

解决方案

As far as I understand your code, it can't produce the stated output. A part of your problem os that you don't reduce the length of your string. There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality. When you don't understand what your code is doing or why it does what it does, the answer is debugger. Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool. Debugger - Wikipedia, the free encyclopedia[^] Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^] Basic Debugging with Visual Studio 2010 - YouTube[^] The debugger is here to show you what your code is doing and your task is to compare with what it should do. There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

Your example removes 2 characters at position 2. There is a std::string method that can do that: std::basic_string::erase - cppreference[^]:

string str = "helloHowAreyou"; str.erase(2, 2); cout << str;

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替换字符串中的元素

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