本文介绍了调用静态泛型方法的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我遇到了一个涉及静态泛型方法的奇怪情况。这是代码:
class Foo< E> { public static< E> FOO< E - 代替; createFoo() { // ... } } class Bar< E> { private Foo< E>会员; public Bar() { member = Foo.createFoo(); $ / code $ / pre我怎么没有指定任何类型表达式中的参数 Foo.createFoo()?这是某种类型推断吗?如果我想明确它,我该如何指定类型参数?
解决方案是的,这是基于该分配的目标,根据 JLS部分15.12.2.8 。明确地说,你可以这样调用:
Foo。< String> createFoo();
I have come across a curious situation involving static generic methods. This is the code:
class Foo<E> { public static <E> Foo<E> createFoo() { // ... } } class Bar<E> { private Foo<E> member; public Bar() { member = Foo.createFoo(); } }How come I don't have to specify any type arguments in the expression Foo.createFoo()? Is this some kind of type inference? If I want to be explicit about it, how can I specify the type argument?
解决方案Yes, this is type inference based on the target of the assignment, as per JLS section 15.12.2.8. To be explicit, you'd call something like:
Foo.<String>createFoo();
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