setter的Lambda表达式

本文介绍了setter的Lambda表达式的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我们可以为getter使用lambda表达式，如下所示

We can lambda expression for getter as below

Function<Student, String> studentNameGetter = Student::getName;

如何为setter创建lambda表达式？

How about creating lambda expression for the setter?

推荐答案

我不确定你为setter创建一个lambda表达式是什么意思。

I'm not sure what you mean by creating a lambda expression for the setter.

您尝试做的是将方法引用分配给合适的功能接口。在这种情况下，最佳匹配是 BiConsumer ：

What it looks like you are trying to do is to assign the method reference to a suitable Functional Interface. In that case, the best match is to a BiConsumer:

BiConsumer<Student, String> studentNameSetter = Student::setName;