延迟任务

本文介绍了延迟任务的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

无法获得任务延迟. 同步完全不会延迟. 异步停止在await Task.Delay(delay);.

Cannot get a Delay in a task. The Sync does not delay at all. The Async stops at await Task.Delay(delay);.

我尝试过:

Task wait4me = Task.Delay(1000); await wait4me;

并且不起作用-停在await wait4me;.

Task<int> TaskOfTResult_MethodSync(int delay) { Debug.WriteLine($"TaskOfTResult_MethodSync delay = {delay} {DateTime.Now}"); int hours = 10; Task.Delay(delay); Debug.WriteLine($"TaskOfTResult_MethodSync after delay {DateTime.Now}"); return Task.FromResult(hours); } async Task<int> TaskOfTResult_MethodAsync(int delay) { Debug.WriteLine($"TaskOfTResult_MethodAsync delay = {delay} {DateTime.Now}"); await Task.Delay(delay); Debug.WriteLine($"After await Task.Delay({delay}) {DateTime.Now}"); int hours = 11; return hours; }

测试

Task<int> task = TaskOfTResult_MethodSync(1000); Debug.WriteLine("before task.Wait"); task.Wait(); Debug.WriteLine("after task.Wait"); int i = task.Result; Debug.WriteLine($"i = {i}"); Debug.WriteLine($""); Task<int> taskA = TaskOfTResult_MethodAsync(1000); Debug.WriteLine("before taskA.Wait"); taskA.Wait(); Debug.WriteLine("after taskA.Wait"); i = taskA.Result; Debug.WriteLine($"i = {i}"); Debug.WriteLine($"");

推荐答案

您可以简单地通过

Task.Delay(delay).Wait()