本文介绍了如何制作一组清单的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个这样的列表列表:
I have a list of lists like this:
i = [[1, 2, 3], [2, 4, 5], [1, 2, 3], [2, 4, 5]]我想要一个包含独特"列表(基于其元素)的列表,如:
I would like to get a list containing "unique" lists (based on their elements) like:
o = [[1, 2, 3], [2, 4, 5]]我不能使用set(),因为列表中有不可散列的元素.相反,我正在这样做:
I cannot use set() as there are non-hashable elements in the list. Instead, I am doing this:
o = [] for e in i: if e not in o: o.append(e)有更简单的方法吗?
推荐答案您可以创建一组元组,由于您提到的不可散列的元素,因此不可能有一组列表.
You can create a set of tuples, a set of lists will not be possible because of non hashable elements as you mentioned.
>>> l = [[1, 2, 3], [2, 4, 5], [1, 2, 3], [2, 4, 5]] >>> set(tuple(i) for i in l) {(1, 2, 3), (2, 4, 5)}更多推荐
如何制作一组清单
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