本文介绍了如何检查视图的存在的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要创建一个脚本来检查视图是否已经存在. 我认为应该这样做,但是只是不想工作:)
I need to create a script that check if a view already exist. I think that this should do this, but there just don't want to work :)
IF EXISTS(select * FROM system.views where name = 'view_name');关于我在做什么错的任何想法吗?
Any ideea about what I'm doing wrong?
推荐答案尝试一下
DECLARE V_COUNT INTEGER; BEGIN select COUNT(*) INTO V_COUNT FROM dba_views where view_name = 'view_name'; -- use dba_views or all_views tables IF V_COUNT > 0 THEN -- your code goes here END IF; END;更多推荐
如何检查视图的存在
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