如何在iPhone中将十进制数字四舍五入为两位数?

编程入门行业动态更新时间:2024-10-18 01:29:38

本文介绍了如何在iPhone中将十进制数字四舍五入为两位数?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

我们如何在iPhone中将十进制数字四舍五入为两位数?

How can we round off decimal numbers to 2 digits in iphone ?

例如，

5345-> 53

5345 --> 53

570-> 57

89523-> 90

89523 -- > 90

我试图为此使用nsformatter，这是我使用的代码，

I tried to use nsformatter for this and here is the code i used ,

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; [formatter setNumberStyle:NSNumberFormatterDecimalStyle]; [formatter setMaximumIntegerDigits:2]; [formatter setRoundingMode: NSNumberFormatterRoundUp]; NSString *numberString = [formatter stringFromNumber:[NSNumber numberWithInt:570]]; [formatter release]; NSLog(@"%@",numberstring);

即使将舍入模式更改为其他选项，我仍继续获得70的值.请帮助我

I keep on getting the value as 70 even after changing the rounding mode to different options. Please help me with this

谢谢，维诺德

推荐答案

使用此简单代码代替格式化程序；

Use this simple code instead of formatter;

myFloat = roundf(100 * myFloat) / 100.0;

我希望能帮上忙.

或者您可以使用此

float roundedValue = round(2.0f * number) / 2.0f; NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; [formatter setMaximumFractionDigits:2]; [formatter setRoundingMode: NSNumberFormatterRoundDown]; NSString *numberString = [formatter stringFromNumber:[NSNumber numberWithFloat:roundedValue]]; [formatter release];

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如何在iPhone中将十进制数字四舍五入为两位数?

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