我如何在F#中编写此成员约束?

编程入门 行业动态 更新时间:2024-10-20 05:29:23
本文介绍了我如何在F#中编写此成员约束?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述

对于类型

类型Cow()= class member this.Walk() = Console.WriteLine(The cow walks。) end

我可以写一个方法强制成员约束的方法Walk像

let inline walk_the_creature creature = (^ a:(member Walk :unit - > unit)creature) //然后做 walk_the_creature(Cow())

在这种情况下,推断类型。我无法明确地写出这样的生物参数约束。

//不编译 //查找基于这个 //程序点之前的信息的不确定类型的对象。可能需要类型注释... let inline walk_the_creature_2(生物:^ a当^ a :(成员步行:单位 - >单位))= creature.Walk()

我做错了什么?

解决方案

它没有明确写出约束是问题,而是语法不够好,您可以将一个成员约束放在一个参数上,然后以通常的方式调用该成员。 walk_the_creature 和 walk_the_creature2 的主体在这里是一样的:

let inline walk_the_creature_2(生物:^ a当^ a :(成员Walk:单位 - >单位))= (^ a :(成员Walk:单位 - >单位)生物)

For a type

type Cow() = class member this.Walk () = Console.WriteLine("The cow walks.") end

I can write a method which enforces a member constrain for method Walk like

let inline walk_the_creature creature = (^a : (member Walk : unit -> unit) creature) // and then do walk_the_creature (Cow())

In this case the type is inferred. I am unable to explicitly write a constraint on the creature parameter like this

// Does not compile // Lookup on object of indeterminate type based on information prior to this // program point. A type annotation may be needed... let inline walk_the_creature_2 (creature:^a when ^a:(member Walk : unit -> unit)) = creature.Walk()

What am I doing wrong?

解决方案

It's not explicitly writing the constraints that is the issue, it's that the syntax is not so nice that you can place a member constraint on a parameter and then invoke the member in the usual way. The body of walk_the_creature and walk_the_creature2 would be the same here:

let inline walk_the_creature_2 (creature:^a when ^a:(member Walk : unit -> unit)) = (^a : (member Walk : unit -> unit) creature)

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我如何在F#中编写此成员约束?

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