为什么在foldLeft中留下点会导致编译错误？

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任何人都可以解释为什么我忽略用于应用 foldLeft 函数的点符号（版本2.9.2）时为什么会看到以下编译错误

Can anyone explain why I see this compile error for the following when I omit the dot notation for applying the foldLeft function?(version 2.9.2)

scala> val l = List(1, 2, 3) res19: List[Int] = List(1 ,2 ,3) scala> l foldLeft(1)(_ * _) <console>:9: error: Int(1) does not take parameters l foldLeft(1)(_ * _) ^

但是

but

scala> l.foldLeft(1)(_ * _) res27: Int = 6

不适用于其他高阶函数，如 map ，它似乎并不关心我是否提供点。

This doesn't hold true for other higher order functions such as map which doesn't seem to care whether I supply the dot or not.

我不认为它是一个关联事物，因为我不能只调用 foldLeft（1）

I don't think its an associativity thing because I can't just invoke foldLeft(1)

推荐答案

这是因为foldLeft是咖喱。除了使用点符号，还可以通过添加圆括号来解决此问题：

It's because foldLeft is curried. As well as using the dot notation, you can also fix this by adding parentheses:

scala> (l foldLeft 1)(_ * _) res3: Int = 6

并且关于您对无法调用 foldLeft（l）的评论，您可以，但您需要像这样部分应用它：

Oh - and regarding your comment about not being able to invoke foldLeft(l), you can, but you need to partially apply it like this:

scala> (l foldLeft 1) _ res3: ((Int, Int) => Int) => Int = <function1>