JavaScript 中的 PHP 和 window.close

本文介绍了JavaScript 中的 PHP 和 window.close的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有问题.我有一个页面，当您单击按钮时，会显示一个带有表单的弹出窗口.所以，我完成了一些数据并提交.我想要做的是，提交表单，关闭表单并刷新父页面.我不想用 AJAX 来做.

I have a problem. I have a page that when you click a button, a popup with a form is shown. So, I complete some data and I submit. What I want to do is, to submit the form, close the form and refresh the parent page. I don't want to do it with AJAX.

问题是在我的父页面中，我必须使用表单的输入信息刷新内容.

The problem is that in my parent page I have to refresh content with the input information of the form.

所以当我刷新时，有时会显示数据，有时不会.你知道为什么会发生这种情况吗?

So when I refresh, sometimes the data is shown and sometimes not. Do you know why this could happen?

我只是在表单中使用 onsubmit="refreshParent()".信息总是存储在我的数据库中，所以我认为问题可能是有时刷新会捕获新信息，有时不会.

I just use onsubmit="refreshParent()" in my form. The info is stored always in my database, so I think the problem may be that sometimes the refresh catches the new info and sometimes not.

function refreshParent() { window.opener.location.reload(); window.close(); }

推荐答案

我用它来重新加载打开弹出窗口的页面:

I use this to reload the page that opened a popup window:

<script language="JavaScript"> <!-- function reloadParentPage() { window.opener.location.href = window.opener.location.href; if (window.opener.progressWindow) { window.opener.progressWindow.close() } window.close(); } //--> </script>

顺便说一下，上面的代码是通过弹出页面中的链接或按钮调用的.

By the way, the code above is called by a link or button in the popup page.