堆栈溢出错误

本文介绍了堆栈溢出错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

下面给出的代码显示了运行时的Stackoverflow错误.但是，如果我使另一个类CarChange创建Car对象，它将成功运行.我是一个初学者，请执行以下代码以了解在Java中进行向上转换的重要性.

The code given below shows a Stackoverflow error when run.But if I make another class CarChange to create objects of Car ,it runs sucessfully. I am a beginner ,doing this code to understand the importance of upcasting in java.

public class Car { int i; Car[] c=new Car[2]; Car() { c[0] = new Polo(); i=0; } void drive(){ c[i].testdrive(); //the overloaded method in subclasses polo and swift } void change() { if(i==0) { i++; c[i] = new Swift(); } } public void testdrive() { //overloaded method in subclasses polo and swift System.out.println(" test drive car"); } //class Tester { //main Car c= new Car(); c.drive(); c.change(); c.drive();

推荐答案

stackoverflow通常意味着您有一个无限循环.

A stackoverflow usually means you have an infinite loop.

收到此消息的原因是因为您正在从testdrive方法调用驱动器，并且在该方法中您再次调用drive.

The reason you're receiving this is because you're calling drive from the testdrive method and in that method you're calling drive again.