std :: thread< unresolved overloaded function type>错误

本文介绍了std :: thread< unresolved overloaded function type>错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想从我的类中生成一个线程，线程在我的类中执行一个特定的方法。代码如下：

I am trying to spawn a thread from within my class and the thread executes a particular method in my class. The code looks like this:

class ThreadClass{ int myThread(int arg){ // do something } void createThread(){ thread t = thread(myThread,10); } } ;

这段代码在编译时会引发一个错误：

This code on compilation throws an error saying

std::thread::thread(_Callable&&, _Args&& ...) [with _Callable = int (ThreadClass::*)(int), _Args = {int}] no known conversion for argument 1 from ‘<unresolved overloaded function type>’ to ‘int (ThreadClass::*&&)(int)’

我不知道这里是什么是实际的错误。有人可以帮我解决这个问题吗？

I am not sure what is the actual bug here. Can someone help me with this?

感谢。

推荐答案

问题是不能在没有对象的情况下调用成员函数。提供指向 的指针，以便使用当前对象：

The problem is that a member function can't be called without an object. Provide a pointer to this so that the current object is used:

thread t(&ThreadClass::myThread, this, 10);

您可以使用任何 ThreadClass 对象，但在你的情况下，看起来这是正确的事情。

You could use an instance of any ThreadClass object, but in your case, it seems this is the right thing to do.

注意：对创建的线程的引用，以便稍后可以执行 join（）。

NOTE: Remember you need a reference to the created thread so that you can do a join() later on.