如何在Laravel中找到哪个“后卫"发出了当前请求?

本文介绍了如何在Laravel中找到哪个“后卫"发出了当前请求?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

这是我的auth.php:

'guards' => [ 'web' => [ 'driver' => 'session', 'provider' => 'users', ], 'admin' => [ 'driver' => 'session', 'provider' => 'admins', ], ],

现在，如果同时在同一浏览器中登录了user和admin，我该如何检查哪个保安提出了请求?

Now, if both a user and an admin are logged-in in the same browser, how do I check which guard made the request?

请注意，无论谁发出请求，Auth::guard('admin')->check()和Auth::check()都将返回true.

Please note that both Auth::guard('admin')->check() and Auth::check() return true no matter who's making the request.

推荐答案

我假设您想知道auth()->user()指的是哪个防护-auth()->guard()

I am assuming you want to know which guard auth()->user() refers to - which is accessible by auth()->guard()

不幸的是，没有一个现成的功能可以实际获得守卫的 name .您可以使用auth()->guard()->getName()，但返回防护的会话标识符(即login_guardname_sha1hash)，但如果需要，可以将其提取:

Unfortunately, there is not an existing function to actually get the name of the guard. You can use auth()->guard()->getName() but that returns the session identifier for the guard (i.e. login_guardname_sha1hash) but if you need it you can extract it:

$guard = auth()->guard(); // Retrieve the guard $sessionName = $guard->getName(); // Retrieve the session name for the guard // The following extracts the name of the guard by disposing of the first // and last sections delimited by "_" $parts = explode("_", $sessionName); unset($parts[count($parts)-1]); unset($parts[0]); $guardName = implode("_",$parts);