四舍五入整数的10最接近的倍数

本文介绍了四舍五入整数的10最接近的倍数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我试图找出如何一轮涨价 - 两种方式。例如：

I am trying to figure out how to round prices - both ways. For example:

Round down 43 becomes 40 143 becomes 140 1433 becomes 1430 Round up 43 becomes 50 143 becomes 150 1433 becomes 1440

我在那里我有发言权的一个价格区间的情况：

I have the situation where I have a price range of say:

£143 - £193

而我想要显示为：

of which I want to show as:

£140 - £200

因为它看起来简洁多了

as it looks a lot cleaner

我如何能做到这一点任何想法？

Any ideas on how I can achieve this?

推荐答案

我只想创造了几个方法;

I would just create a couple methods;

int RoundUp(int toRound) { return (10 - toRound % 10) + toRound; } int RoundDown(int toRound) { return toRound - toRound % 10; }

模给我们的余数，在围捕 10的情况下 - R的带你到最近的十分之一，为本轮下跌你刚才减河pretty直线前进。

Modulus gives us the remainder, in the case of rounding up 10 - r takes you to the nearest tenth, to round down you just subtract r. Pretty straight forward.