在一个范围内生成一个随机偶数?

本文介绍了在一个范围内生成一个随机偶数?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

这是我遵循的格式:

int randomNum = rand.nextInt((max - min) + 1) + min;

这是我的代码.我正在尝试获取 1 到 100 之间的随机偶数:

So here's my code. I'm trying to get a random even number between 1 and 100:

Random rand = new Random(); int randomNum = rand.nextInt((100 - 2) + 1) + 2;

我看到一种解决方案是将数字乘以 2，但这超出了预期范围.

I saw one solution is to multiply the number by 2, but that breaches the intended range.

我想过做一堆if语句来解决这个问题，但似乎过于复杂.有没有比较简单的解决办法?

I thought of doing a bunch of if statements to solve this, but it seems overly complex. Is there a relatively simple solution?

推荐答案

只需生成一个从 0 到 49 的数字，然后将其乘以 2.

Just generate a number from 0 to 49 and then multiply it by 2.

Random rand = new Random(); int randomNum = rand.nextInt(100/2) *2;

要在一个范围内进行，只需将范围添加到:

To do it in a range just add the range in:

int randomNum = startOfRange+rand.nextInt((endOfRange-startOfRange)/2) *2;

注意 startOfRange 应该是偶数或转换成偶数.

Note that startOfRange should be an even number or converted into an even number.