本文介绍了对象数组列表-最小值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个对象数组列表,并且这些对象具有双精度"值.我需要打印出所有对象,并首先打印出具有最高值的对象,最后打印出具有最低值的对象.
I have an arraylist of objects, and the objects have "double" values. I need to print out all the objects, and have the object with the highest value printed first, and the object with the lowest value last.
我也曾尝试使用Collections对arraylist进行排序,然后进行打印,但是我似乎无法使其正常工作.
I have also tried to use Collections to sort the arraylist and then print, but I can't seem to get it to work.
我的数组列表是:
ArrayList<Transition> transitions = new ArrayList<Transition>();当我尝试使用收藏集时,我使用了:
When i tried to used Collections i used:
Object minValue = Collections.min(transitions);希望你们中的一些人可以提供帮助:)
Hope some of you can help :)
推荐答案如果Transition对象实现了Comparable接口,请尝试这种方式.应该可以.
If Transition object implemented Comparable interface try this way. It should work.
Collections.sort(transitions); Transition transition = transitions.get(0);更多推荐
对象数组列表
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