Pygame 显示模块初始化和退出

本文介绍了Pygame 显示模块初始化和退出的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

打开一个 pygame.display 窗口，我调用 pygame.display.quit() 来销毁窗口.因为需要再次打开窗口，所以调用了pygame.display.init()和pygame.display.set_mode()，但是这两个函数调用后，什么也没有发生.谁能指出这个问题的根源?

Having a pygame.display window open, I call pygame.display.quit() upon it in order to destroy the window. Because I need to open the window again, I call pygame.display.init() and pygame.display.set_mode(), but after these two functions are called, nothing happens. Can anyone point me to the root of this problem?

推荐答案

这是带有 gui 模块的示例代码...每当您调用 screen_off() 时，显示就会退出.每当您希望显示恢复时，请输入您之前使用的所有内容以将其打开.

Here is example code with a gui module... Whenever you call screen_off() then the display quits. Whenever you want display to come back, type everything you used before to turn it on.

如果需要，请使用 pygame.display.quit()，不要在 screen_off() 函数中使用它.我建议把你用来打开显示器的所有代码都放在一个函数中，这样你就不必在它被杀死后再次输入它来打开它.

If you want, use pygame.display.quit(), without it being inside the screen_off() function. I suggest taking all the code you used to get the display on, and putting it into a function so you don't have to type it again to turn it on after it's been killed.

from pygame import * from pygame.locals import * import pygame, pygame.locals from easygui import * def screen_off(): pygame.display.quit() pygame.init() canvas = pygame.display.set_mode((400,400),0,32) red = (255,0,0) canvas.fill(red) pygame.display.update() screen_off() #display is now OFF... choice = ['Yes', 'No'] cc = buttonbox('Continue?', "Options", choice) if cc == "Yes": #if you don't want to type these arguments below again to turn on the display then #put them into a function and call it pygame.init() canvas = pygame.display.set_mode((400,400),0,32) purple = (204,0,204) canvas.fill(purple) pygame.display.update() #display is now ON...