本文介绍了PHP正则表达式在字符串的开头查找任何数字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用 PHP,希望能够创建一个正则表达式来查找并返回地址的街道号码部分.
I'm using PHP, and am hoping to be able to create a regex that finds and returns the street number portion of an address.
示例:
1234- 南大道.华盛顿特区,APT #306,ZIP45234
1234- South Blvd. Washington D.C., APT #306, ZIP45234
在上面的例子中,只会返回 1234.
In the above example, only 1234 would be returned.
看起来这应该非常简单,但我还没有成功.任何帮助将不胜感激.
Seems like this should be incredibly simple, but I've yet to be successful. Any help would be greatly appreciated.
推荐答案试试这个:
$str = "1234- South Blvd. Washington D.C., APT #306, ZIP4523"; preg_match("~^(\d+)~", $str, $m); var_dump($m[1]);输出:
string(4) "1234"更多推荐
PHP正则表达式在字符串的开头查找任何数字
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