如何使用正则表达式匹配任何重复的字符？

但Go的正则表达式似乎不允许这样做。是否可以在Go中执行此操作？

由于反向引用是不受re2支持，您需要：

• 要么使用另一个正则表达式库（如 glenn-brown / golang-pkg-pcre ）
• 或编写循环，无需regexp即可进行分析
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I need to match any character that's repeated twice, for example:

"abccdeff"

Should match "cc" and "ff". In any other regex syntax, let's use Javascript as a quick example, I could do:

var str = "abccdeff"; var r = /([a-z]{1})\1/g console.log(str.match(r))

Which returns

[ 'cc', 'ff' ]

But Go's regexp doesn't seem to allow that. Is it possible to do this in Go?

解决方案

Since backreference is not supported by re2, you would need:

• either to use another regex library (like glenn-brown/golang-pkg-pcre)
• or code a loop which does the analysis without regexp