我需要匹配任何重复两次的字符,例如:
abccdeff匹配cc和ff。在任何其他正则表达式语法中,我们使用Javascript作为一个简单的例子,我可以这样做:
var str =abccdeff; var r = /([az] {1})\ 1 / g console.log(str.match(r))其中返回
['cc','ff']但Go的正则表达式似乎不允许这样做。是否可以在Go中执行此操作?
解决方案由于反向引用是不受re2支持,您需要: I need to match any character that's repeated twice, for example: Should match "cc" and "ff". In any other regex syntax, let's use Javascript as a quick example, I could do: Which returns But Go's regexp doesn't seem to allow that. Is it possible to do this in Go? Since backreference is not supported by re2, you would need:
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如何使用正则表达式匹配任何重复的字符?
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