Javascript正则表达式匹配字符串中以“＃”开头的任何单词

本文介绍了Javascript正则表达式匹配字符串中以“＃”开头的任何单词的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我是正则表达式的新手。我试图在一个不包含换行符的字符串中匹配以'＃'开头的任何单词（内容已经在换行符处拆分）。

I'm very new at regex. I'm trying to match any word that starts with '#' in a string that contains no newlines (content was already split at newlines).

示例（不工作） ：

var string = "#iPhone should be able to compl#te and #delete items" var matches = string.match(/(?=[\s*#])\w+/g) // Want matches to contain [ 'iPhone', 'delete' ]

我正在尝试匹配任何'＃'实例，并在它之后抓住它，只要至少有一个字母，数字或跟随它的符号。空格或换行符应该结束匹配。 '＃'应该以字符串开头或以空格开头。

I am trying to match any instance of '#', and grab the thing right after it, so long as there is at least one letter, number, or symbol following it. A space or a newline should end the match. The '#' should either start the string or be preceded by spaces.

这个PHP解决方案看起来不错，但它使用的是向后看的类型的功能，我不这样做知道JS正则表达式是否： 正则表达式保留/匹配任何以某个字符开头的单词

This PHP solution seems good, but it uses a look backwards type of functionality that I don't know if JS regex has: regexp keep/match any word that starts with a certain character

推荐答案

var re = /(?:^|\W)#(\w+)(?!\w)/g, match, matches = []; while (match = re.exec(s)) { matches.push(match[1]); }

检查 此演示 。

Check this demo.