序列化对象的XmlDocument

本文介绍了序列化对象的XmlDocument的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

为了返回 SoapException.Detail 有用的信息，为ASMX web服务，我从WCF的想法，并创建了一个故障类含有该有用的信息。断层对象被序列化到所需的的XmlNode 的抛出的SoapException 。

我不知道是否我有最好的code创建的XmlDocument - 这里是我对吧：

VAR的XmlDocument =新的XmlDocument（）;VAR串行器=新的XmlSerializer（typeof运算（T））;使用（VAR流=新的MemoryStream（））{    serializer.Serialize（流theObjectContainingUsefulInformation）;    stream.Flush（）;    stream.Seek（0，SeekOrigin.Begin）;    XMLDocument.load方法（流）;}

是否有这样做的更好的办法？

更新：其实我最终执行以下操作，因为除非你包在＆LT XML的代码;详情＆GT; XML元素，你会得到一个 SoapHeaderException 在客户端为：

VAR serialiseToDocument =新的XmlDocument（）;VAR串行器=新的XmlSerializer（typeof运算（T））;使用（VAR流=新的MemoryStream（））{    serializer.Serialize（流e.ExceptionContext）;    stream.Flush（）;    stream.Seek（0，SeekOrigin.Begin）;    serialiseToDocument.Load（流）;}//删除XML声明serialiseToDocument.RemoveChild（serialiseToDocument.FirstChild）;//记着我们希望节点VAR serialisedNode = serialiseToDocument.FirstChild;//，敷在＆LT;详情＆GT;元件VAR rootNode中= serialiseToDocument.CreateNode（XmlNodeType.Element，细节，）;rootNode.AppendChild（serialisedNode）;

更新2：由于约翰·桑德斯出色答卷，我现在已经开始使用下列内容：

私有静态无效SerialiseFaultDetail（）{    VAR值=新ServiceFault                    {                        消息=异常发生                        错误code = 1010                    };    //序列化到XML文档    VAR detailDocument =新的XmlDocument（）;    VAR NAV = detailDocument.CreateNavigator（）;    如果（NAV！= NULL）    {        使用（XmlWriter的作家= nav.AppendChild（））        {            VAR SER =新的XmlSerializer（fault.GetType（））;            ser.Serialize（作家，故障）;        }    }    //记着并删除我们想要的元素    XmlNode的infoNode = detailDocument.FirstChild;    detailDocument.RemoveChild（infoNode）;    //移动到根＆LT;详情＆GT;元件    VAR rootNode中= detailDocument.AppendChild（detailDocument.CreateNode（XmlNodeType.Element，细节，））;    rootNode.AppendChild（infoNode）;    Console.WriteLine（detailDocument.OuterXml）;    Console.ReadKey（）;}

解决方案

编辑：创建细节元素中输出

公共类MyFault{    公众诠释错误code {搞定;组; }    公共字符串的ErrorMessage {搞定;组; }}公共静态的XmlDocument SerializeFault（）{    VAR值=新MyFault                    {                        错误code = 1，                        的ErrorMessage =这是一个错误                    };    VAR faultDocument =新的XmlDocument（）;    VAR NAV = faultDocument.CreateNavigator（）;    使用（VAR作家= nav.AppendChild（））    {        VAR SER =新的XmlSerializer（fault.GetType（））;        ser.Serialize（作家，故障）;    }    VAR detailDocument =新的XmlDocument（）;    VAR detailElement = detailDocument.CreateElement（        EXC        SoapException.DetailElementName.Name，        SoapException.DetailElementName.Namespace）;    detailDocument.AppendChild（detailElement）;    detailElement.AppendChild（        detailDocument.ImportNode（            faultDocument.DocumentElement，真））;    返回detailDocument;}

In order to return useful information in SoapException.Detail for an asmx web service, I took an idea from WCF and created a fault class to contain said useful information. That fault object is then serialised to the required XmlNode of a thrown SoapException.

I'm wondering whether I have the best code to create the XmlDocument - here is my take on it:

var xmlDocument = new XmlDocument(); var serializer = new XmlSerializer(typeof(T)); using (var stream = new MemoryStream()) { serializer.Serialize(stream, theObjectContainingUsefulInformation); stream.Flush(); stream.Seek(0, SeekOrigin.Begin); xmlDocument.Load(stream); }

Is there a better way of doing this?

UPDATE: I actually ended up doing the following, because unless you wrap the XML in a <detail> xml element, you get a SoapHeaderException at the client end:

var serialiseToDocument = new XmlDocument(); var serializer = new XmlSerializer(typeof(T)); using (var stream = new MemoryStream()) { serializer.Serialize(stream, e.ExceptionContext); stream.Flush(); stream.Seek(0, SeekOrigin.Begin); serialiseToDocument.Load(stream); } // Remove the xml declaration serialiseToDocument.RemoveChild(serialiseToDocument.FirstChild); // Memorise the node we want var serialisedNode = serialiseToDocument.FirstChild; // and wrap it in a <detail> element var rootNode = serialiseToDocument.CreateNode(XmlNodeType.Element, "detail", ""); rootNode.AppendChild(serialisedNode);

UPDATE 2: Given John Saunders excellent answer, I've now started using the following:

private static void SerialiseFaultDetail() { var fault = new ServiceFault { Message = "Exception occurred", ErrorCode = 1010 }; // Serialise to the XML document var detailDocument = new XmlDocument(); var nav = detailDocument.CreateNavigator(); if (nav != null) { using (XmlWriter writer = nav.AppendChild()) { var ser = new XmlSerializer(fault.GetType()); ser.Serialize(writer, fault); } } // Memorise and remove the element we want XmlNode infoNode = detailDocument.FirstChild; detailDocument.RemoveChild(infoNode); // Move into a root <detail> element var rootNode = detailDocument.AppendChild(detailDocument.CreateNode(XmlNodeType.Element, "detail", "")); rootNode.AppendChild(infoNode); Console.WriteLine(detailDocument.OuterXml); Console.ReadKey(); }

解决方案

EDIT: Creates output inside of detail element

public class MyFault { public int ErrorCode { get; set; } public string ErrorMessage { get; set; } } public static XmlDocument SerializeFault() { var fault = new MyFault { ErrorCode = 1, ErrorMessage = "This is an error" }; var faultDocument = new XmlDocument(); var nav = faultDocument.CreateNavigator(); using (var writer = nav.AppendChild()) { var ser = new XmlSerializer(fault.GetType()); ser.Serialize(writer, fault); } var detailDocument = new XmlDocument(); var detailElement = detailDocument.CreateElement( "exc", SoapException.DetailElementName.Name, SoapException.DetailElementName.Namespace); detailDocument.AppendChild(detailElement); detailElement.AppendChild( detailDocument.ImportNode( faultDocument.DocumentElement, true)); return detailDocument; }