为了返回 SoapException.Detail 有用的信息,为ASMX web服务,我从WCF的想法,并创建了一个故障类含有该有用的信息。断层对象被序列化到所需的的XmlNode 的抛出的SoapException 。
我不知道是否我有最好的code创建的XmlDocument - 这里是我对吧:
VAR的XmlDocument =新的XmlDocument();VAR串行器=新的XmlSerializer(typeof运算(T));使用(VAR流=新的MemoryStream()){ serializer.Serialize(流theObjectContainingUsefulInformation); stream.Flush(); stream.Seek(0,SeekOrigin.Begin); XMLDocument.load方法(流);}是否有这样做的更好的办法?
更新:其实我最终执行以下操作,因为除非你包在&LT XML的代码;详情> XML元素,你会得到一个 SoapHeaderException 在客户端为:
VAR serialiseToDocument =新的XmlDocument();VAR串行器=新的XmlSerializer(typeof运算(T));使用(VAR流=新的MemoryStream()){ serializer.Serialize(流e.ExceptionContext); stream.Flush(); stream.Seek(0,SeekOrigin.Begin); serialiseToDocument.Load(流);}//删除XML声明serialiseToDocument.RemoveChild(serialiseToDocument.FirstChild);//记着我们希望节点VAR serialisedNode = serialiseToDocument.FirstChild;//,敷在<详情>元件VAR rootNode中= serialiseToDocument.CreateNode(XmlNodeType.Element,细节,);rootNode.AppendChild(serialisedNode);更新2:由于约翰·桑德斯出色答卷,我现在已经开始使用下列内容:
私有静态无效SerialiseFaultDetail(){ VAR值=新ServiceFault { 消息=异常发生 错误code = 1010 }; //序列化到XML文档 VAR detailDocument =新的XmlDocument(); VAR NAV = detailDocument.CreateNavigator(); 如果(NAV!= NULL) { 使用(XmlWriter的作家= nav.AppendChild()) { VAR SER =新的XmlSerializer(fault.GetType()); ser.Serialize(作家,故障); } } //记着并删除我们想要的元素 XmlNode的infoNode = detailDocument.FirstChild; detailDocument.RemoveChild(infoNode); //移动到根<详情>元件 VAR rootNode中= detailDocument.AppendChild(detailDocument.CreateNode(XmlNodeType.Element,细节,)); rootNode.AppendChild(infoNode); Console.WriteLine(detailDocument.OuterXml); Console.ReadKey();}解决方案
编辑:创建细节元素中输出
公共类MyFault{ 公众诠释错误code {搞定;组; } 公共字符串的ErrorMessage {搞定;组; }}公共静态的XmlDocument SerializeFault(){ VAR值=新MyFault { 错误code = 1, 的ErrorMessage =这是一个错误 }; VAR faultDocument =新的XmlDocument(); VAR NAV = faultDocument.CreateNavigator(); 使用(VAR作家= nav.AppendChild()) { VAR SER =新的XmlSerializer(fault.GetType()); ser.Serialize(作家,故障); } VAR detailDocument =新的XmlDocument(); VAR detailElement = detailDocument.CreateElement( EXC SoapException.DetailElementName.Name, SoapException.DetailElementName.Namespace); detailDocument.AppendChild(detailElement); detailElement.AppendChild( detailDocument.ImportNode( faultDocument.DocumentElement,真)); 返回detailDocument;}In order to return useful information in SoapException.Detail for an asmx web service, I took an idea from WCF and created a fault class to contain said useful information. That fault object is then serialised to the required XmlNode of a thrown SoapException.
I'm wondering whether I have the best code to create the XmlDocument - here is my take on it:
var xmlDocument = new XmlDocument(); var serializer = new XmlSerializer(typeof(T)); using (var stream = new MemoryStream()) { serializer.Serialize(stream, theObjectContainingUsefulInformation); stream.Flush(); stream.Seek(0, SeekOrigin.Begin); xmlDocument.Load(stream); }Is there a better way of doing this?
UPDATE: I actually ended up doing the following, because unless you wrap the XML in a <detail> xml element, you get a SoapHeaderException at the client end:
var serialiseToDocument = new XmlDocument(); var serializer = new XmlSerializer(typeof(T)); using (var stream = new MemoryStream()) { serializer.Serialize(stream, e.ExceptionContext); stream.Flush(); stream.Seek(0, SeekOrigin.Begin); serialiseToDocument.Load(stream); } // Remove the xml declaration serialiseToDocument.RemoveChild(serialiseToDocument.FirstChild); // Memorise the node we want var serialisedNode = serialiseToDocument.FirstChild; // and wrap it in a <detail> element var rootNode = serialiseToDocument.CreateNode(XmlNodeType.Element, "detail", ""); rootNode.AppendChild(serialisedNode);UPDATE 2: Given John Saunders excellent answer, I've now started using the following:
private static void SerialiseFaultDetail() { var fault = new ServiceFault { Message = "Exception occurred", ErrorCode = 1010 }; // Serialise to the XML document var detailDocument = new XmlDocument(); var nav = detailDocument.CreateNavigator(); if (nav != null) { using (XmlWriter writer = nav.AppendChild()) { var ser = new XmlSerializer(fault.GetType()); ser.Serialize(writer, fault); } } // Memorise and remove the element we want XmlNode infoNode = detailDocument.FirstChild; detailDocument.RemoveChild(infoNode); // Move into a root <detail> element var rootNode = detailDocument.AppendChild(detailDocument.CreateNode(XmlNodeType.Element, "detail", "")); rootNode.AppendChild(infoNode); Console.WriteLine(detailDocument.OuterXml); Console.ReadKey(); }解决方案
EDIT: Creates output inside of detail element
public class MyFault { public int ErrorCode { get; set; } public string ErrorMessage { get; set; } } public static XmlDocument SerializeFault() { var fault = new MyFault { ErrorCode = 1, ErrorMessage = "This is an error" }; var faultDocument = new XmlDocument(); var nav = faultDocument.CreateNavigator(); using (var writer = nav.AppendChild()) { var ser = new XmlSerializer(fault.GetType()); ser.Serialize(writer, fault); } var detailDocument = new XmlDocument(); var detailElement = detailDocument.CreateElement( "exc", SoapException.DetailElementName.Name, SoapException.DetailElementName.Namespace); detailDocument.AppendChild(detailElement); detailElement.AppendChild( detailDocument.ImportNode( faultDocument.DocumentElement, true)); return detailDocument; }
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