本文介绍了将Ionic Zip读取为Memory Stream C#的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用Ionic.Zip通过以下方法将ZipFile提取到内存流中:
I am using Ionic.Zip to extract ZipFile to memory stream with this method:
private MemoryStream GetReplayZipMemoryStream() { MemoryStream zipMs = new MemoryStream(); using (ZipFile zip = ZipFile.Read(myFile.zip)) { foreach (ZipEntry zipEntry in zip) { if (zipEntry.FileName.StartsWith("Aligning") || zipEntry.FileName.StartsWith("Sensing")) { zipEntry.Extract(zipMs); } } } zipMs.Seek(0, SeekOrigin.Begin); return zipMs; }完成提取后,我想读取流并根据条目文件名获取一些条目.我该怎么办?
Once I am done extracting, I want to read the streams and get some of the entries based on the entry filename. How can I do that?
我尝试使用下面的代码进行调用,但是在ZipFile.Read(ms)上显示错误:
I tried by calling with the code below, but I get error on the ZipFile.Read(ms) which said:
无法将其读取为ZipFile
Cannot read that as a ZipFile
Stream ms = GetReplayZipMemoryStream(); using (ZipFile zip = ZipFile.Read(ms)) { ZipEntry imageEntry = zip.Entries.First(x => x.FileName.EndsWith(".png")); using (Stream s = imageEntry.OpenReader()) { var image = Image.FromStream(s); pictureBox1.Image = image; } }
预先感谢您的帮助!
推荐答案这可能是个有点老的问题和较晚的答案,但我已经做了一些事情来将文件作为字节集合及其文件名
This may be little bit old question and late answer but I have did something to get the files as bytes collections and its file names like this
public static Dictionary<string, byte[]> Decompress(Stream targFileStream) { Dictionary<string, byte[]> files = new Dictionary<string, byte[]>(); using(ZipFile z = ZipFile.Read(targFileStream)) { foreach (ZipEntry zEntry in z) { MemoryStream tempS = new MemoryStream(); zEntry.Extract(tempS); files.Add(zEntry.FileName, tempS.ToArray()); } } return files; }更多推荐
将Ionic Zip读取为Memory Stream C#
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