也许这是一个愚蠢的问题,但是我正在开发一个项目,希望我生成一些如下所示的JSON :
Maybe this is a silly question, but I'm working on a project that wants me to generate some JSON that looks like this:
{'action.type':'post', 'application':APP_ID}在C#中,我试图使用"post"的值创建此"action.type"属性.我该怎么做?这是我典型地创建诸如以下内容的方式:
In C#, I'm trying to create this "action.type" attribute, with the value of "post". How would I do that? Here's how I've typlically been creating stuff like:
dynamic ActionSpec = new ExpandoObject(); ActionSpec.SomeParam = "something"; ActionSpec.id = 12345;我无法使用"ActionSpec.action.type",因为那样将不会输出所需的"action.type". 这有意义吗? 谢谢!
I can't go "ActionSpec.action.type", because that will not output the desired "action.type". Does this make sense? Thanks!
推荐答案您可以尝试通过字典填充它:
You could try populating it via the dictionary:
IDictionary<string, object> expandoDictionary = ActionSpec; expandoDictionary["action.type"] = "post";但是,如果它拒绝将其作为无效标识符,我将不会感到惊讶.
However, I wouldn't be at all surprised if it rejected that as an invalid identifier.
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