如何传递非静态成员函数作为回调？

本文介绍了如何传递非静态成员函数作为回调？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

io_iterator_t enumerator; kern_return_t result; result = IOServiceAddMatchingNotification( mNotifyPort, kIOMatchedNotification, IOServiceMatching( "IOFireWireLocalNode" ), serviceMatchingCallback, (void *)0x1234, & enumerator );

serviceMatchingCallback((void *)0x1234, enumerator);

如果我声明serviceMatchinCallback作为静态，那么它工作，但我不想它静态。有没有办法传递它一个非静态的回调函数？

if i declare serviceMatchinCallback as static then it works, but i do not want it to be static. Is there a way to pass it a non-static callback function?

谢谢

推荐答案

你可以保持它的静态，但使用userdata存储这个指针，除了你想要的其他用户数据（通过打包成一个结构，例如），然后通过调用 this-> someCallback （其中 this 是存储在userdata中的指针，当然）。

You could keep it static, but use the userdata to store the this pointer in addition to whatever other userdata you want (by packing them into a structure, for example) and then call an object-specific callback from the static version by calling this->someCallback (where this is the pointer stored in the userdata, of course).