本文介绍了JsonParser返回null而不是值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个简单的Jackson解析器,该解析器应该向我返回值,但只获取null值.任何想法将不胜感激?
I have a simple Jackson parser, that is supposed to return me values but instead am getting only null values. Any ideas will be appreciated?
示例Json数据:
{"a":"ab","b":"cd","c":"cd","d":"de","e":"ef","f":"fg"}代码:
var jfactory = new JsonFactory() var jParser : JsonParser = jfactory.createJsonParser(new File(outputDir + "/" + "myDic.json")) while (jParser.nextToken() != JsonToken.END_OBJECT) { var k = jParser.getCurrentName(); jParser.nextToken(); var v = jParser.getText(); println(k +"---" + v) phoneDict.put(k,v); i = i + 1; println(phoneDict.size) var t = readLine("Dict Done ?") }输出:
null---null 1 Dict Done ? null---null 1 Dict Done ? null---null 1 Dict Done ? null---null 1 Dict Done ?推荐答案
我的Java代码如下所示:
My Java code looks like this and works perfectly fine:
JsonFactory jsonFactory = new JsonFactory(); JsonParser jsonParser = jsonFactory.createParser(json); //Skip START_OBJECT jsonParser.nextToken(); while (JsonToken.END_OBJECT != jsonParser.nextToken()) { System.out.println(jsonParser.getCurrentName()); jsonParser.nextToken(); System.out.println(jsonParser.getText()); }更多推荐
JsonParser返回null而不是值
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