JsonParser返回null而不是值

本文介绍了JsonParser返回null而不是值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个简单的Jackson解析器，该解析器应该向我返回值，但只获取null值.任何想法将不胜感激?

I have a simple Jackson parser, that is supposed to return me values but instead am getting only null values. Any ideas will be appreciated?

示例Json数据:

{"a":"ab","b":"cd","c":"cd","d":"de","e":"ef","f":"fg"}

代码:

var jfactory = new JsonFactory() var jParser : JsonParser = jfactory.createJsonParser(new File(outputDir + "/" + "myDic.json")) while (jParser.nextToken() != JsonToken.END_OBJECT) { var k = jParser.getCurrentName(); jParser.nextToken(); var v = jParser.getText(); println(k +"---" + v) phoneDict.put(k,v); i = i + 1; println(phoneDict.size) var t = readLine("Dict Done ?") }

输出:

null---null 1 Dict Done ? null---null 1 Dict Done ? null---null 1 Dict Done ? null---null 1 Dict Done ?

推荐答案

我的Java代码如下所示:

My Java code looks like this and works perfectly fine:

JsonFactory jsonFactory = new JsonFactory(); JsonParser jsonParser = jsonFactory.createParser(json); //Skip START_OBJECT jsonParser.nextToken(); while (JsonToken.END_OBJECT != jsonParser.nextToken()) { System.out.println(jsonParser.getCurrentName()); jsonParser.nextToken(); System.out.println(jsonParser.getText()); }