好,这是正在发生的事情的概述:
Ok here is an overview of what's going on:
M <-- Message with unique id of 1234 | +-Start Queue | | | <-- Exchange /|\ / | \ / | \ <-- bind to multiple queues Q1 Q2 Q3 \ | / <-- start of the problem is here \ | / \ | / \|/ | Q4 <-- Queues 1,2 and 3 must finish first before Queue 4 can start | C <-- Consumer所以我有一个交换,它推送到多个队列,每个队列都有一个任务,一旦所有任务完成,队列4才能启动.
So I have an exchange that pushes to multiple queues, each queue has a task, once all tasks are completed, only then can Queue 4 start.
因此,唯一ID为1234的消息被发送到交换机,当消息ID 1234的所有任务都已完成时,交换机将其路由到所有任务队列(Q1,Q2,Q3等)邮件ID为1234的第4季度.
So message with unique id of 1234 gets sent to the exchange, the exchange routes it to all the task queues ( Q1, Q2, Q3, etc... ), when all the tasks for message id 1234 have completed, run Q4 for message id 1234.
我该如何实现?
使用Symfony2,RabbitMQBundle和RabbitMQ 3.x
Using Symfony2, RabbitMQBundle and RabbitMQ 3.x
资源:
- www.rabbitmq/tutorials/amqp-concepts.html
- www.rabbitmq/tutorials/tutorial-six-python.html
- www.rabbitmq/tutorials/amqp-concepts.html
- www.rabbitmq/tutorials/tutorial-six-python.html
更新#1
好吧,我认为这就是我想要的:
Ok I think this is what I'm looking for:
- github/videlalvaro/Thumper/tree/master/examples/parallel_processing
具有并行处理功能的RPC,但是如何将相关性ID"设置为我的唯一ID,以对消息进行分组并确定哪个队列?
RPC with Parallel Processing, but how do I set the Correlation Id to be my unique id to group the messages and also identify what queue?
推荐答案在 RabbitMQ网站上的RPC 教程,提供了一种传递关联ID"的方法,该ID可以向队列中的用户标识您的消息.
In the RPC tutorial at RabbitMQ's site, there is a way to pass around a 'Correlation id' that can identify your messages to users in the queue.
我建议对您的消息使用某种ID,将其放入前3个队列中,然后再进行另一个处理,以将消息从这3个队列中取出并放入某种存储桶中.当这些存储桶收到我假设的3个任务的完成时,请将最终消息发送到第4个队列进行处理.
I'd recommend using some sort of id with your messages into the first 3 queues and then have another process to dequeue messages from the 3 into buckets of some sort. When those buckets receive what I'm assuming is the completion of there 3 tasks, send the final message off to the 4th queue for processing.
如果要向一个用户的每个队列发送一个以上的工作项目,则可能需要做一些预处理,以找出特定用户放入队列中的项目数,以便在4之前出队的进程知道有多少要处理的项目.在排队之前期待.
If you are sending more than 1 work item to each queue for one user, you might have to do a little preprocessing to find out how many items a particular user placed into the queue so the process dequeuing before 4 knows how many to expect before queuing up.
我用C#编写Rabbitmq,所以抱歉,我的伪代码不是php风格
I do my rabbitmq in C#, so sorry my pseudo code isn't in php style
// Client byte[] body = new byte[size]; body[0] = uniqueUserId; body[1] = howManyWorkItems; body[2] = command; // Setup your body here Queue(body)// Server // Process queue 1, 2, 3 Dequeue(message) switch(message.body[2]) { // process however you see fit } processedMessages[message.body[0]]++; if(processedMessages[message.body[0]] == message.body[1]) { // Send to queue 4 Queue(newMessage) }
响应更新#1
将客户端视为服务器上的进程可能会有用,而不是将客户端视为终端.因此,如果您在此服务器,那么您要做的就是让服务器处理用户唯一ID的生成并将消息发送到适当的队列:
Instead of thinking of your client as a terminal, it might be useful to think of the client as a process on a server. So if you setup an RPC client on a server like this one, then all you need to do is have the server handle the generation of a unique id of a user and send the messages to the appropriate queues:
public function call($uniqueUserId, $workItem) { $this->response = null; $this->corr_id = uniqid(); $msg = new AMQPMessage( serialize(array($uniqueUserId, $workItem)), array('correlation_id' => $this->corr_id, 'reply_to' => $this->callback_queue) ); $this->channel->basic_publish($msg, '', 'rpc_queue'); while(!$this->response) { $this->channel->wait(); } // We assume that in the response we will get our id back return deserialize($this->response); } $rpc = new Rpc(); // Get unique user information and work items here // Pass even more information in here, like what queue to use or you could even loop over this to send all the work items to the queues they need. $response = rpc->call($uniqueUserId, $workItem); $responseBuckets[array[0]]++; // Just like above code that sees if a bucket is full or not更多推荐
RabbitMQ等待多个队列完成
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