有没有办法使用的wait()系统调用超时,除了使用忙等待或忙睡眠循环?
Is there any way to use the wait() system call with a timeout, besides using a busy-waiting or busy-sleeping loop?
我已经得到了叉父进程取值本身和 EXEC 是个孩子的可执行文件。然后等待孩子来完成,通过一切适当手段抓住它的输出,以及并进行进一步处理。如果该过程不的一段时间内完成,则认为其执行超时,并执行别的东西。不幸的是,这个超时检测是必要的,因为该问题的性质
I've got a parent process that forks itself and execs a child executable. It then waits for the child to finish, grabs its output by whatever means appropriate, and and performs further processing. If the process does not finish within a certain period of time, it assumes that its execution timed out, and does something else. Unfortunately, this timeout detection is necessary given the nature of the problem.
推荐答案有不等待调用了超时。
你可以做的,而不是为安装设置SIGCHLD标志的信号处理程序,并使用select()来执行超时。选择()将由信号中断。
What you can do instead is install a signal handler that sets a flag for SIGCHLD, and use select() to implement a timeout. select() will be interrupted by a signal.
static volatile int punt; static void sig_handler(int sig) { punt = 1; } ... struct timeval timeout = {10,0}; int rc; signal(SIGCHLD, sig_handler); fork/exec stuff //select will get interrupted by a signal rc = select(0, NULL,NULL,NULL, &tv); if (rc == 0) { // timed out } else if (punt) { //child terminated }如果你有其他的信号,你需要处理以及需要更多的逻辑,虽然
More logic is needed if you have other signal you need to handle as well though
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是否有等待()系统调用设置一个超时的版本?
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