我有一个随机日期列表,格式如下:
I have a list of random dates formatted like:
String x ="Text("key:[2020-08-23 22:22, 2020-08-22 10:11, 2020-02-22 12:14]"),"我可以使用 d{4}-d{2}-d{2}sd{2}:d{2} 正则表达式来匹配所有x 中的日期:
I can use the d{4}-d{2}-d{2}sd{2}:d{2} regex to match all dates in x:
RegExp regExp79 = new RegExp( r'd{4}-d{2}-d{2}sd{2}:d{2}', ); var match79 = regExp79.allMatches("$x"); var mylistdate = match79;所以,匹配是:
match 1 = 2020-08-22 22:22 match 2 = 2020-08-22 10:11 match 3 = 2020-02-22 12:14我想将 Iterable 转换成一个字符串列表,这样我的列表的输出看起来像:
I want to convert the Iterable<RegExpMatch> into a list of strings, so that the output of my list looks like:
[2020-08-22 22:22, 2020-08-22 10:11, 2020-02-22 12:14] 推荐答案allMatches 方法 返回一个 Iterable 值.它包含所有 RegExpMatch 包含有关匹配的一些详细信息的对象.您需要在每个 RegExpMatch 对象上调用 .group(0) 方法来获取匹配的字符串值.
The allMatches method returns an Iterable<RegExpMatch> value. It contains all the RegExpMatch objects that contain some details about the matches. You need to invoke the .group(0) method on each RegExpMatch object to get the string value of the match.
所以,你需要.map结果:
your_regex.allMatches(x).map((z) => z.group(0)).toList()代码:
String x ="Text("key:[2020-08-23 22:22, 2020-08-22 10:11, 2020-02-22 12:14]"),"; RegExp regExp79 = new RegExp(r'd{4}-d{2}-d{2}sd{2}:d{2}'); var mylistdate = regExp79.allMatches(x).map((z) => z.group(0)).toList(); print(mylistdate);输出:
[2020-08-23 22:22, 2020-08-22 10:11, 2020-02-22 12:14]更多推荐
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