我有一个随机日期列表,格式如下:
I have a list of random dates formatted like:
String x ="Text(\"key:[2020-08-23 22:22, 2020-08-22 10:11, 2020-02-22 12:14]\"),"我可以使用 \d {4} \-\d {2} \-\d {2} \s\d {2}:\d {2} 正则表达式可匹配 x :
I can use the \d{4}\-\d{2}\-\d{2}\s\d{2}:\d{2} regex to match all dates in x:
RegExp regExp79 = new RegExp( r'\d{4}\-\d{2}\-\d{2}\s\d{2}:\d{2}', ); var match79 = regExp79.allMatches("$x"); var mylistdate = match79;因此,匹配项为:
match 1 = 2020-08-22 22:22 match 2 = 2020-08-22 10:11 match 3 = 2020-02-22 12:14我想将 Iterable< RegExpMatch> 转换为字符串列表,以便输出我的列表如下:
I want to convert the Iterable<RegExpMatch> into a list of strings, so that the output of my list looks like:
[2020-08-22 22:22, 2020-08-22 10:11, 2020-02-22 12:14]推荐答案
allMatches 方法返回 Iterable< RegExpMatch> 值。它包含所有 RegExpMatch 对象,其中包含有关匹配项的一些详细信息。您需要在每个 RegExpMatch 对象上调用 .group(0)方法以获取匹配项的字符串值。
The allMatches method returns an Iterable<RegExpMatch> value. It contains all the RegExpMatch objects that contain some details about the matches. You need to invoke the .group(0) method on each RegExpMatch object to get the string value of the match.
因此,您需要 .map 结果:
your_regex.allMatches(x).map((z) => z.group(0)).toList()代码:
String x ="Text(\"key:[2020-08-23 22:22, 2020-08-22 10:11, 2020-02-22 12:14]\"),"; RegExp regExp79 = new RegExp(r'\d{4}-\d{2}-\d{2}\s\d{2}:\d{2}'); var mylistdate = regExp79.allMatches(x).map((z) => z.group(0)).toList(); print(mylistdate);输出:
[2020-08-23 22:22, 2020-08-22 10:11, 2020-02-22 12:14]更多推荐
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