本文介绍了根据正则表达式匹配对字符串列表进行排序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个文本文件,看起来像:
I have a text file that looks a bit like:
random text random text, can be anything blabla %A blabla random text random text, can be anything blabla %D blabla random text random text, can be anything blabla blabla %F random text random text, can be anything blabla blabla random text random text, %C can be anything blabla blabla当我输入readlines()时,它变成一个句子列表.现在,我希望此列表按%之后的字母排序.因此,基本上,将排序应用于上面的内容时,应该看起来像这样:
When I readlines() it in, it becomes a list of sentences. Now I want this list to be sorted by the letter after the %. So basically, when the sort is applied to the above, it should look like:
random text random text, can be anything blabla %A blabla random text random text, %C can be anything blabla blabla random text random text, can be anything blabla %D blabla random text random text, can be anything blabla blabla %F random text random text, can be anything blabla blabla是否有一个好方法,或者我必须将每个字符串分成小管,然后将字母移动到特定列,然后使用key=operator.itemgetter(col)进行排序?
Is there a good way to do this, or will I have to break each string in to tubles, and then move the letters to a specific column, and then sort using key=operator.itemgetter(col)?
谢谢
推荐答案In [1]: def grp(pat, txt): ...: r = re.search(pat, txt) ...: return r.group(0) if r else '&' In [2]: y Out[2]: ['random text random text, can be anything blabla %A blabla', 'random text random text, can be anything blabla %D blabla', 'random text random text, can be anything blabla blabla %F', 'random text random text, can be anything blabla blabla', 'random text random text, %C can be anything blabla blabla'] In [3]: y.sort(key=lambda l: grp("%\w", l)) In [4]: y Out[4]: ['random text random text, can be anything blabla %A blabla', 'random text random text, %C can be anything blabla blabla', 'random text random text, can be anything blabla %D blabla', 'random text random text, can be anything blabla blabla %F', 'random text random text, can be anything blabla blabla']
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根据正则表达式匹配对字符串列表进行排序
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