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问题描述
任何人都可以共享的样本code如何在开始推出Android应用程序/开机的设备?
Can anybody share the sample code to how to launch android application upon starting/booting up the device?
推荐答案这code将推出在启动一个应用程序。你需要听 ACTION_BOOT_COMPLETE 。
This code will launch an application on start up. You need to listen for ACTION_BOOT_COMPLETE.
in AndroidManifest.xml (application-part): <receiver android:enabled="true" android:name=".BootUpReceiver" android:permission="android.permission.RECEIVE_BOOT_COMPLETED"> <intent-filter> <action android:name="android.intent.action.BOOT_COMPLETED" /> <category android:name="android.intent.category.DEFAULT" /> </intent-filter> </receiver> [..] <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" /> [..] public class BootUpReceiver extends BroadcastReceiver{ @Override public void onReceive(Context context, Intent intent) { Intent i = new Intent(context, MyActivity.class); i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); context.startActivity(i); } }更多推荐
如何启动时启动了设备的应用程序?
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