将zip解压缩到内存中，解析内容

本文介绍了将zip解压缩到内存中，解析内容的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想将zip文件的内容读取到内存中，而不是将其提取到光盘中，在存档中找到特定文件，打开文件并从中提取一行.

I want to read the contents of a zip file into memory rather than extracting them to disc, find a particular file in the archive, open the file and extract a line from it.

可以打开并解析StringIO实例吗?有什么建议吗?预先感谢.

Can a StringIO instance be opened and parsed? Suggestions? Thanks in advance.

zfile = ZipFile('name.zip', 'r') for name in zfile.namelist(): if fnmatch.fnmatch(name, '*_readme.xml'): name = StringIO.StringIO() print name # prints StringIO instances open(name, 'r') # IO Error: No such file or directory...

我发现了一些类似的帖子，但似乎都没有解决这个问题:提取zipfile记忆?

I found a few similar posts, but none that seem to address this issue: Extracting a zipfile to memory?

推荐答案

感谢所有提供解决方案的人.这就是对我有用的东西:

Thank you to everyone that contributed solutions. This is what ended up working for me:

zfile = ZipFile('name.zip', 'r') for name in zfile.namelist(): if fnmatch.fnmatch(name, '*_readme.xml'): zopen = zfile.open(name) for line in zopen: if re.match('(.*)<foo>(.*)</foo>(.*)', line): print line