检索F#函数的MethodInfo

本文介绍了检索F#函数的MethodInfo的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想编写一个将函数f作为参数并返回与f相关联的System.Reflection.MethodInfo的函数.

I would like to write a function that takes a function f as an argument and returns the System.Reflection.MethodInfo associated to f.

我不太确定这是否可行.

I'm not quite sure if it is feasible or not.

推荐答案

因此，我终于找到了解决方案.很hacky，但是嘿！有用！ (仅在调试"模式下).

So, I finally found a solution. Very hacky, but hey! It works! (edit: in Debug mode only).

let Foo (f:S -> A[] -> B[] -> C[] -> D[] -> unit) = let ty = f.GetType() let argty = [|typeof<S>; typeof<A[]>; typeof<B[]>; typeof<C[]>;typeof<D[]>|] let mi = ty.GetMethod("Invoke", argty) let il = mi.GetMethodBody().GetILAsByteArray() let offset = 9//mi.GetMethodBody().MaxStackSize let token = System.BitConverter.ToInt32(il, offset) let mb = ty.Module.ResolveMethod(token) match Expr.TryGetReflectedDefinition mb with | Some ex -> printfn "success %A" e | None -> failwith "failed"

即使f是在另一个程序集(.dll)中定义的，也可以在Foo调用的同一位置定义，它仍然可以正常工作. 由于我必须定义什么是argty，所以还不是很全面，但是我敢肯定我可以编写一个实现该功能的函数.

It works well, even if f is defined in another assembly (.dll) or in the same where the call of Foo happens. It's not fully general yet since I have to define what argty is, but I'm sure I can write a function that does it.

在编写此代码后发现，尽管在C#中，Dustin对于相同的问题也有类似的解决方案(请参见此处执行的调用方法).

Turns out after writing this code that Dustin have a similar solution for the same issue, albeit in C# (see it here).

所以这是一个用法示例:

So here's an usage example:

open System open Microsoft.FSharp.Quotations [<ReflectedDefinition>] let F (sv:int) (a:int[]) (b:int[]) (c:int[]) (d:int[]) = let temp = a.[2] + b.[3] c.[0] <- temp () let Foo (f:S -> A[] -> B[] -> C[] -> D[] -> unit) = let ty = f.GetType() let arr = ty.BaseType.GetGenericArguments() let argty = Array.init (arr.Length-1) (fun i -> arr.[i]) let mi = ty.GetMethod("Invoke", argty) let il = mi.GetMethodBody().GetILAsByteArray() let offset = 9 let token = System.BitConverter.ToInt32(il, offset) let mb = ty.Module.ResolveMethod(token) mb let main () = let mb = Foo F printfn "%s" mb.Name match Expr.TryGetReflectedDefinition mb with | None -> () | Some(e) -> printfn "%A" e do main ()

它的作用是打印F的名称，如果功能是反映的定义，则打印它的AST.

What it does is printing name of F, and its AST if the function is a reflected definition.

但是经过进一步调查后，发现此hack仅在调试模式下有效(并且F必须是函数值以及顶级定义)，因此也可以说这是不可能要做的事情.

But after further investigation, it happens that this hack only works in debug mode (and F has to be a function value as well as a top level definition), so might as well say that it's an impossible thing to do.

这是调试/发布版本中FSharpFunc的Invoke方法的IL代码:

Here's the IL code of the FSharpFunc's Invoke method in both debug/release build:

调试模式:

.method /*06000007*/ public strict virtual instance class [FSharp.Core/*23000002*/]Microsoft.FSharp.Core.Unit/*01000006*/ Invoke(int32 sv, int32[] a, int32[] b, int32[] c, int32[] d) cil managed // SIG: 20 05 12 19 08 1D 08 1D 08 1D 08 1D 08 { // Method begins at RVA 0x21e4 // Code size 16 (0x10) .maxstack 9 IL_0000: /* 00 | */ nop IL_0001: /* 03 | */ ldarg.1 IL_0002: /* 04 | */ ldarg.2 IL_0003: /* 05 | */ ldarg.3 IL_0004: /* 0E | 04 */ ldarg.s c IL_0006: /* 0E | 05 */ ldarg.s d IL_0008: /* 28 | (06)000001 */ call void Program/*02000002*/::F(int32, int32[], int32[], int32[], int32[]) /* 06000001 */ IL_000d: /* 00 | */ nop IL_000e: /* 14 | */ ldnull IL_000f: /* 2A | */ ret } // end of method mb@25::Invoke

释放模式:

method public strict virtual instance class [FSharp.Core]Microsoft.FSharp.Core.Unit Invoke(int32 sv, int32[] a, int32[] b, int32[] c, int32[] d) cil managed { // Code size 28 (0x1c) .maxstack 7 .locals init ([0] int32 V_0) IL_0000: nop IL_0001: ldarg.2 IL_0002: ldc.i4.2 IL_0003: ldelem [mscorlib]System.Int32 IL_0008: ldarg.3 IL_0009: ldc.i4.3 IL_000a: ldelem [mscorlib]System.Int32 IL_000f: add IL_0010: stloc.0 IL_0011: ldarg.s c IL_0013: ldc.i4.0 IL_0014: ldloc.0 IL_0015: stelem [mscorlib]System.Int32 IL_001a: ldnull IL_001b: ret } // end of method mb@25::Invoke

您可以看到在释放模式下，编译器将F的代码内联到Invoke方法中，因此调用F的信息(以及检索令牌的可能性)消失了..

You can see that in release mode, the compiler inlines code of F into the Invoke method, so the information of calling F (and the possibility to retrieve the token) is gone..