查找一些词典的通用键

本文介绍了查找一些词典的通用键的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有大约20000个字典。我想找到所有字典中都通用的所有键（该键必须在所有20000个字典中都存在）。如何实现这一目标。目前，我正在写类似的东西，但是它没有给我期望的结果：

I have around 20000 dictionaries.I want find all the keys which are common in all the dictionary(that key need to be present in all 20000) dictionary.How can I achieve this.Currently I am writing something like that,But its not giving me the desired result:

if parsedData.keys() not in uniquelist: uniquelist.append(parsedData.keys()) else: commonlist.append(parsedData.keys())

这里解析的数据是我的字典。

here parsed data is my dictionary. Please help me with this.

推荐答案

您可以在第一个字典中创建一组键，然后以循环形式创建

You could create the set of the keys in the first dictionary and then in a loop form the intersection with the remaining keys:

>>> d1 = {'a':1, 'b':2, 'c':3} >>> d2 = {'b':4, 'c':7,'d':5} >>> d3 = {'b':5, 'c':8,'e':6} >>> dicts = [d1,d2,d3] >>> common_keys = set(d1.keys()) >>> for d in dicts[1:]: common_keys.intersection_update(set(d.keys())) >>> common_keys {'b', 'c'}