在目标C（Mac OS X）中检测CPU体系结构（32位/ 64位）运行时

本文介绍了在目标C（Mac OS X）中检测CPU体系结构（32位/ 64位）运行时的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我目前正在拧可可应用程序，该应用程序需要执行一些（控制台）针对32位和64位进行了优化的应用程序。因此，我想检测应用程序正在运行的CPU体系结构，以便启动正确的控制台应用程序。

I'm currently wring a Cocoa application which needs to execute some (console) applications which are optimized for 32 and 64 bit. Because of this I would like to detect what CPU architecture the application is running on so I can start the correct console application.

因此，简而言之：如何检测是否应用程序在64位操作系统上运行？

So in short: how do I detect if the application is running on a 64 bit OS?

编辑：我知道 Mach-O 胖二进制文件，这不是我的问题。我需要知道这一点，因此我可以启动另一个非捆绑（控制台）应用程序。一种针对 x86 进行了优化，另一种针对 x64 。

I know about the Mach-O fat binaries, that was not my question. I need to know this so I can start another non bundled (console) application. One that is optimized for x86 and one for x64.

推荐答案

有一种超级简单的方法。编译可执行文件的两个版本，一个用于32位，一个用于64位，然后将它们与lipo结合在一起。这样，正确的版本将始终得到执行。

There is a super-easy way. Compile two versions of the executable, one for 32-bit and one for 64-bit and combine them with lipo. That way, the right version will always get executed.

gcc -lobjc somefile.m -o somefile -m32 -march=i686 gcc -lobjc somefile.m -o somefile2 -m64 -march=x86_64 lipo -create -arch i686 somefile -arch x86_64 somefile2 -output somefileUniversal

编辑：或者首先使用 gcc -arch i686 -arch x86_64

响应OP的评论：

if(sizeof(int*) == 4) //system is 32-bit else if(sizeof(int*) == 8) //system is 64-bit

编辑：哦！我没有意识到您需要运行时检查...通过 sysctl -A 的输出，两个变量看起来很有用。尝试解析 sysctl hw.optional.x86_64 和 sysctl hw.cpu64bit_capable 的输出。我没有32位Mac可以测试，但是在Core2Duo Mac上的Snow Leopard中，这两个都设置为1。

D'oh! I didn't realise you'd need runtime checking... Going through the output of sysctl -A, two variables look potentially useful. Try parsing the output of sysctl hw.optional.x86_64 and sysctl hw.cpu64bit_capable . I don't have a 32-bit Mac around to test this, but both these are set to 1 in Snow Leopard on a Core2Duo Mac.