使用Bash重命名文件，删除前缀和后缀

本文介绍了使用Bash重命名文件，删除前缀和后缀的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想使用bash重命名一堆文件，以转换此文件模式:

I want to rename a bunch of files using bash, transforming this file pattern:

prefix - name - suffix.txt

进入这一个:

name.txt

为此，我编写了以下脚本:

For that I wrote the following script:

find . -name "*.txt" | while read f do mv "${f}" "${f/prefix - /}" done find . -name "*.txt" | while read f do mv "${f}" "${f/ - suffix/}" done

它可以工作，但是我想使用一个循环来执行重命名.有可能吗?

It works, but I'd like to perform the renaming using a single loop. Is it possible?

推荐答案

另一种使用正则表达式的方法很有趣:

Another approach, for fun, using regular expressions:

regex='prefix - (.*) - suffix.txt' for f in *.txt; do [[ $f =~ $regex ]] && mv "$f" "${BASH_REMATCH[1]}.txt" done

实际上，在这里使用简单模式'* .txt'存在两个问题:

Actually, using the simple pattern '*.txt' here has two problems:

范围太广；您可能需要将正则表达式应用于许多不匹配的文件.

如果当前目录中有很多个文件，则命令行可能会溢出.

It's too broad; you may need to apply the regex to a lot of non-matching files.

If there are a lot of files in the current directory, the command line could overflow.

使用find使过程复杂，但更正确:

Using find complicates the procedure, but is more correct:

find . -maxdepth 1 -regex 'prefix - .* - suffix.txt' -print0 | \ while read -d '' -r; do [[ $REPLY =~ $regex ]] && mv "$REPLY" "${BASH_REMATCH[1]}.txt" done