测试两个列表是否相等

本文介绍了测试两个列表是否相等的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

说我在Python中有两个列表列表，

Say I have two lists of lists in Python,

l1 = [['a',1], ['b',2], ['c',3]] l2 = [['b',2], ['c',3], ['a',1]]

在l1的元素只是l2中的元素的某种排列的意义上，测试它们是否相等的最优雅的方法是什么?

What is the most elegant way to test they are equal in the sense that the elements of l1 are simply some permutation of the elements in l2?

请注意对普通列表执行此操作请参见此处，但这使用了不适用于列表列表.

Note to do this for ordinary lists see here, however this uses set which does not work for lists of lists.

推荐答案

l1 = [['a',1], ['b',2], ['c',3]] l2 = [['b',2], ['c',3], ['a',1]] print sorted(l1) == sorted(l2)

结果:

True